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OverLord2011 [107]
3 years ago
11

The box part of the box plot contains all the values between which numbers? A box-and-whisker plot. The number line goes from 25

to 50. The whiskers range from 27 to 40, and the box ranges from 32 to 37. A line divides the box at 36. between 27 and 36 and between 37 and 40 between 32 and 36 between 32 and 37 between 27 and 32 and between 37 and 40
Mathematics
2 answers:
bezimeni [28]3 years ago
6 0

Answer:

I believe the answer is C, im doing this on Edg right now and the only thing that looks resonable is C.

Step-by-step explanation:

C matches the plot. Doing the test right now.

NARA [144]3 years ago
5 0

Answer:

B) 32-36

Step-by-step explanation:

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In isosceles ΔABC, AC = BC, AB = 6 in, CD ⊥ AB, and CD = 3 in. Find the perimeter of the isosceles triangle.
Hoochie [10]

Answer:

Step-by-step explanation:

Consider the given triangle ABC, we have AC = BC, AB = 6 in, CD ⊥ AB, and CD = 3 in. Using ΔCDB, we have

(CB)^{2}=(CD)^{2}+(DB)^{2}

(CB)^{2}=(3)^{2}+(3)^{2}

CB=\sqrt{9+9}

CB=\sqrt{18}in

Therefore, CB=CA=\sqrt{18}in (Given)

Now, Perimeter of an isosceles triangle is given By: 2a+b

⇒2(\sqrt{18})+6=2(4.24)+6=8.48+6=14.48in

which is the required perimeter of isosceles triangle.

6 0
3 years ago
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A different class has 285 students, and 51.2% of them are men. how many men are in the class?​
Zanzabum

Answer:

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Step-by-step explanation:

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3 years ago
Simplified 1100/2500
velikii [3]

Answer:

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Step-by-step explanation:

we can divide both top/bottom by 100, to get 11/25

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3 years ago
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Rufina [12.5K]

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2 years ago
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Given sin(−θ)=−1/6 and tanθ=−√35/35 What is the value of cosθ?
murzikaleks [220]

Answer:

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Step-by-step explanation:

Recall the negative angle identity for the sine function:

sin(- \theta)=-sin(\theta)  

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sin(\theta)=-sin(-\theta)\\sin(\theta) =-(-\frac{1}{6} )\\sin(\theta)= \frac{1}{6}

Now recall the definition of the tangent function:

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

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tan(\theta)=\frac{sin(\theta)}{cos(\theta)}\\-\frac{\sqrt{35} }{35} =\frac{1/6}{cos(\theta)} \\cos(\theta)=-\frac{\frac{1}{6} }{\frac{\sqrt{35} }{35} } \\cos(\theta)=-\frac{35}{6\,\sqrt{35} } \\cos(\theta)=-\frac{\sqrt{35} }{6}

5 0
3 years ago
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