5 tenths multuplied by the sum of y and 3 and 3 tenths
Answer:
whichever one corresponds with the answers you have will be right.
Answer:
The probability that the average score of the 49 golfers exceeded 76 is 0.0228
Step-by-step explanation:
To find the probability that the average score of the 49 golfers exceeded 76, we need to calculate z-score of the score 76.
Z-score can be calculated as follows:
z= where
- X=76
- M is the mean score of all golfers (75)
- s is the standard deviation of the scores (3.5)
- N is the sample size (49)
then z(76)= = 2
By looking at the z-table we find that the probability of z-values of scores smaller or equal to 2 is Pr(Z<2)=0.9772. Therefore
The probability that the average score of the 49 golfers exceeded 76 is 1-0.9772=0.0228
For this it would simply be part over whole to figure out the percentage we would do (239/817)*100. This comes out to around 29.25% of the students are remote