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daser333 [38]
3 years ago
9

The length of a photograph of Mr. Lemley playing golf is 1475 inches. If the area

Mathematics
1 answer:
Mice21 [21]3 years ago
8 0

Answer:

1.12 × 10^-3

Step-by-step explanation:

The computation of the width of the photograph is as follows:

As we know that

Area of the rectangle = length × width

33 ÷ 20 square inches = 1475 inches × width

So, the width is

= Length ÷ area

=  1475 inches ÷ (33 ÷ 20 square inches)

= 1.12 × 10^-3

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he equation of a line is written as y=mx+b where m is the slope and b is the

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Five less than 3 times the length, l
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3 years ago
An employer has a staff of eighty actuaries, ten of whom are student actuaries. A student actuary is allowed a total of ten week
sergiy2304 [10]

Answer:

0.1111

Step-by-step explanation:

From the given information;

Number of staffs in the actuary = 80

Out of the 80, 10 are students.

i.e.

P(student actuary) = 10/80 = 0.125

number of weeks in a year = 52

off time per year = 10/52 = 0.1923

P(at work || student actuary) = (50 -10/52)

= 42/52

= 0.8077

P(non student actuary) = (80 -10)/80

= 70 / 80

= 0.875

For a non-student, they are only eligible to 4 weeks off in a year

i.e.

P(at work | non student) = (52-4)/52

= 48/52

= 0.9231

∴

P(at work) = P(student actuary) × P(at work || student actuary) + P(non student actuary) × P(at work || non studnet actuary)

P(at work) =  (0.125 × 0.8077) + ( 0.875 × 0.9231)

P(at work) = 0.1009625 + 0.8077125

P(at work) = 0.90868

Finally, the P(he is a student) = (P(student actuary) × P(at work || student actuary) ) ÷ P(at work)

P(he is a student) = (0.125 × 0.8077) ÷ 0.90868

P(he is a student) = 0.1009625 ÷ 0.90868

P(he is a student) = 0.1111

5 0
3 years ago
18 ≥ -2x <br> i cant solve this
Bumek [7]

Answer:

x\geq -9

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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