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Alina [70]
3 years ago
15

The linear equation of the initial (red ) incline would be y = __x +__

Mathematics
1 answer:
RideAnS [48]3 years ago
3 0

Answer:

y=\underline {1.5}x+\underline 0

Step-by-step explanation:

From the graph,

The initial red incline is a straight line passing through the origin.

So, a straight line passing through the origin is of the form:

y=mx+0

Where, 'm' is the slope.

Now, the slope of a given as the change in y value to change in x value.

Consider the two end points of the red line (0, 0) and (4, 6).

The slope with two points (x_1,y_1)\ and\ (x_2,y_2) on the line is given as:

m=\frac{(y_2-y_1)}{(x_2-x_1)}

Plug in x_1=0,y_1=0,x_2=4,y_2=6. Therefore, slope is:

m=\frac{6-0}{4-0}\\m=\frac{6}{4}=1.5

Hence, the equation of the initial red incline is:

y=\underline {1.5}x+\underline 0

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Likurg_2 [28]

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x = -8/29 = -0.276

Step-by-step explanation:

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Processing ends successfully

plz mark me as brainliest :)

5 0
3 years ago
Read 2 more answers
GIVING BRAINLIEST
andriy [413]
D would be the highest value
4 0
3 years ago
Read 2 more answers
HELPP
Harrizon [31]

Answer:

Step-by-step explanation:

Alright, lets get started.

Lets find slope for both bikes one by one

For bike 1 :

There are two points on the graph of Bike 1, these two points are (2,3) and (4,6)

So the slope for bike 1 is : \frac{y_{2}-y_{1} }{x_{2}-x_{1} }

So the slope for bike 1 is : \frac{6-3}{4-2}

So the slope for bike 1 is : \frac{3}{2}

For bike 2 :

There are two points on the graph of Bike 2, these two points are (4,5) and (8,10)

So the slope for bike 2 is : \frac{y_{2}-y_{1} }{x_{2}-x_{1} }

So the slope for bike 2 is : \frac{10-5}{8-4}=\frac{5}{4}

Hence Bike 1 will win the race as slope of line bike1 is greater than slope of line bike 2.  So, answer is option D


3 0
3 years ago
Read 2 more answers
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