$k:12x-5y=2\to-5y=-12x+2\ \ \ /:(-5)\to y=\frac{12}{5}y-\frac{2}{5}\\\\l:y=mx+b\\\\k\ ||\ l\iff m=\frac{12}{5}\\\\ l:y=\frac{12}{5}x+b;\ (2;\ 3)\\\\\frac{12}{5}\cdot2+b=3\\\\\frac{24}{5}+b=3\\\\b=\frac{15}{5}-\frac{24}{5}\\\\b=-\frac{9}{5}\\\\Answer:y=\frac{12}{5}x-\frac{9}{5}\to\frac{12}{5}x-y=\frac{9}{5}\ \ \ \ /\cdot5\to12x-5y=9$

7 0

3 years ago

What is the area of a sector in a circle of radius 8cm,if the angle between the radii is 30°

IceJOKER [234]

Answer:

16.75 square cm

Step-by-step explanation:

$Area \: of \: sector = \frac{ \theta}{360 \degree} \times \pi {r}^{2} \\ \\ = \frac{30 \degree}{360 \degree} \times 3.14 \times {8}^{2} \\ \\ = \frac{1}{12} \times 3.14 \times 64 \\ \\ = \frac{1}{3} \times 3.14 \times 16 \\ \\ = \frac{1}{3} \times 50.24 \\ \\ = 16.7466667 \\ \\Area \: of \: sector = 16.75 \: {cm}^{2}$

3 0

3 years ago

Which equation represents an exponential function with an initial value of 500 ?

Sergeeva-Olga [200]

Answer: f(x) = 500(2)^x

3 0

3 years ago