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Effectus [21]
3 years ago
15

Find the velocity, v(t), for an object moving along the x-axis if the acceleration, a(t), is a(t) = 3t^2 + cos(t) and v(0) = 2.

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
6 0
\bf \displaystyle a(t)=3t^2+cos(t)\implies \stackrel{velocity}{\int~ [3t^2+cos(t)]dt}\\\\\\ t^3+sin(t)+C=~~~v(t)
\\\\\\
\begin{cases}
v(0)=2\\
v=2\\
t=0
\end{cases}\implies 0^3+sin(0)+C=2\implies C=2
\\\\\\
\boxed{t^3+sin(t)+2=v(t)}
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