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netineya [11]
3 years ago
13

What is the HCF of 216 ​

Mathematics
1 answer:
rjkz [21]3 years ago
8 0

Answer:

The answer for this question is 1

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You have a cookie recipe that calls for 1/3 cup of sugar. You want to make 3 times as many cookies by tripling the recipe. How m
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Answer:

You will need 1 cup of sugar

Step-by-step explanation:

1/3*3/1=3/3=1

4 0
3 years ago
Which equation can be used to represent "six added to twice the sum of a number and four is equal to one-half of the difference
UkoKoshka [18]

Answer:

6+(2x+4)=1/2-(3+x) okay I hope this is it.

Good luck on this.

6 0
4 years ago
a frog can jump 2 feet. how many jumps are needed for the frog to cover a distance of at least 13 feet ?
Ugo [173]
To get 13 feet, it needs to jump 6 and 1/2 jumps, but to get the smallest number past 13, 7 jumps are needed to get a distance of 14 feet
6 0
3 years ago
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For the given hypothesis test, determine the probability of a Type II error or the power, as specified. A hypothesis test is to
erica [24]

Answer:

the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251

Option A) is the correct answer.

Step-by-step explanation:

Given the data in the question;

we know that a type 11 error occur when a null hypothesis is false and we fail to reject it.

as in it in the question;

obtained mean is 9.8 which is obviously not equal to 8.3

But still we fail to reject the null hypothesis says mean is 8.3

Hence we have to find the probability of type 11 error

given that; it is right tailed and o.5, it corresponds to 1.645

so

z is equal to 1.645

z = (x-μ)/\frac{S}{\sqrt{n} }

where our standard deviation s = 3.8

sample size n = 50

mean μ = 8.3

we substitute

1.645 = (x - 8.3)/\frac{3.8}{\sqrt{50} }

1.645 = (x - 8.3) / 0.5374

0.884023 = x - 8.3

x = 0.884023 + 8.3

x = 9.18402

so, by general rule we will fail to reject the null hypothesis when we will get the z value less than 1.645

As we reject the null hypothesis for right tailed test when the obtained test statistics is greater than the critical value

so, we will fail to reject the null hypothesis as long as we get the sample mean less than 9.18402

Now, for mean 9.8 and standard deviation 3.8 and sample size 50

Z =  (9.18402 - 9.8)/\frac{3.8}{\sqrt{50} }

Z = -0.61598 / 0.5374

Z = - 1.1462 ≈ - 1.15

from the z-score table;

P(z<-1.15) = 0.1251

Therefore, the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251

Option A) is the correct answer.

8 0
3 years ago
Which describes condensation?
IrinaK [193]

Answer:

C

Step-by-step explanation:

7 0
3 years ago
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