<span>The car will stop in 140.625 ft
</span>
Answer:
The population proportion is estimated to be with 99% confidence within the interval (0.1238, 0.2012).
Step-by-step explanation:
The formula for estimating the population proportion by a confidence interval is given by:

Where:
is the sample's proportion of success, which in this case is the people that regularly lie during surveys,
is the critical value needed to find the tails of distribution related to the confidence level,
is the sample's size.
<u>First</u> we compute the
value:

<u>Next</u> we find the z-score at any z-distribution table or app (in this case i've used StatKey):

Now we can replace in the formula with the obtained values to compute the confidence interval:

Answer:
B. Train B
Step-by-step explanation:
We are told that Milford and Pinkerton is 300 miles away.
Train A leaves Milford at 10:00 am. There are 3 hours between 10:00 am to 1:00 pm. So let us find distance traveled by train A in 3 hours.



Since train A will cover 270 miles in 3 hours and distance between Milford and Pinkerton is 300 miles, therefore, train A will not arrive Pinkerton before 1:00 pm.
Since there are 5 hours between 8:00 am to 1:00 pm, so let us find distance traveled by train B in 5 hours.


Since train B will cover 350 miles in 5 hours, therefore, train B will arrive Pinkerton before 1:00 pm and option B is the correct choice.
3×2=692047 82837=284749×2484r133.e9274