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Anna35 [415]
2 years ago
11

Is 34/18 greater or less than or equal to 1 5/6

Mathematics
2 answers:
Harlamova29_29 [7]2 years ago
5 0

Answer:

greater than

Step-by-step explanation:

1=6/6 and 6+5=11, so 1 5/6= 11/6

Next, you want to find a common denominator, in this case 18

11/6=x/18

x=33

11/6=33/18

34/18 > 33/18

Galina-37 [17]2 years ago
4 0

Answer:

34/18 is greater than 1 5/6.

Step-by-step explanation:

hope this helps. . .<3

good luck!    uωu

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What is the y-intercept of the function, represented by the table of values below? x: -2,1,2,4,7 y: 14,8,6,2,-4
anastassius [24]

Answer:

The y-intercept is at y = 10.

Step-by-step explanation:

It will be between y = 14 and y = 7 because the corresponding x values are -2 and 1.

An increase of 3 units of x  gives a decrease of 6 units of y fro the above values.

Then an increase of 1 ( 1 to 2) in x gives decrease in y of 2 (8 to 6). The other values show the same pattern.

So very unit increase in x,  the y values change by -2.

So  from x = -2 to 0 is +2 units for x and this will be -4 units for y  so the y-intercept ( when x = 0) will be at y = 14-4 = 10

y-intercept  is (0,10).


7 0
2 years ago
KM and NP are parallel lines. Which angles are corresponding angles?
Charra [1.4K]

Answer:

nol and klj

Step-by-step explanation:

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5 0
3 years ago
1. What number decreased by 9 is 25? (0.5 pt)
Blizzard [7]

Answer:

34

Step-by-step explanation:

x - 9 = 25

x=25+9

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4 0
3 years ago
Would I need Circumference or Area to calculate the distance around a circular track?
Hatshy [7]

Answer:

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Hope this helped!

4 0
2 years ago
Read 2 more answers
Polygon q is a scaled copy of polygon p using a scale factor of 1/2 polygon q’s area is what fraction of polygon p’s area?
san4es73 [151]

Answer:

Polygon q’s area is one fourth of polygon p’s area

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z-----> the scale factor

x-----> polygon q’s area

y-----> polygon p’s area

so

z^{2} =\frac{x}{y}

In this problem we have

z=\frac{1}{2}

substitute

(\frac{1}{2})^{2} =\frac{x}{y}

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x=\frac{1}{4}y

therefore

Polygon q’s area is one fourth of polygon p’s area

3 0
2 years ago
Read 2 more answers
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