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alina1380 [7]
3 years ago
10

Kate made tables of values to solve a system of equations. First she found that the x-value of the solutionwas between 0 and 1,

and then she found it was between 0.5 and 1. Next, she made this table.
Which ordered pair is the best approximation of the solution?

A. (0.8, 2.1)
B. (0.9, 1.8)
C. (0.7, 1.9)
D. (0.6, 1.3)

Mathematics
1 answer:
Blizzard [7]3 years ago
4 0

Answer:

  D. (0.6, 1.3)

Step-by-step explanation:

The difference between y-values is smallest for x=0.6. The approximate y-value is reasonably chosen as the average of the y-values for that value of x.

  (x, y) = (0.6, 1.3) is a reasonable approximation

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The equation of the given Absolute Value Function is; y = |-2x + 4|

<h3>How to interpret Linear Graphs?</h3>

We can see that the given graph is a Linear graph but since it is V-shaped, we can say that it is a graph of an absolute value function.

Now, from the graph we see that;

At x = 0, y = 4

At x = 1, y = 2

At x = 2, y = 0

At x = 3, y = -2

At x = 4, y = 0

At x = 5, y = 2

We can see that the y-intercept is at y = 4.

Slope between two consecutive points is;

(2 - 4)/(1 - 0) = -2

Equation is; y = -2x + 4

Now, this is an absolute value function and as such we will write it as;

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2 years ago
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const2013 [10]
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ycow [4]

It's pretty much simple. Since we can factor a polynomial by its zeros, lets write one of degree nine :

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This polynomial is of degree 9 and has exactly 5 strictly positive zeros : 1, 2, 3, 4, 5

And it has 3 negative zeros : - 1, -1, - 3

And it has 0 as a zero too.

There is also this one :

(X-1)(X-2)(X-3)(X-4)(X²+1)(X+1)(X+2)(X+3) = X^9-4X^8-13X^7+52X^6+35X^5-140X^4+13X^3-52X^2-36X+144

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2 years ago
Write the slipe-intercept form of the equation of each line given the slope and y-intercept.
Eddi Din [679]

Answer:

1. -1/2

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3. 1/2/2

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Step-by-step explanation:

Hope it helped

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3 years ago
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Maurinko [17]

\left(3.5\times 10^{-2}\dfrac{kg}{L}\right)\times\left(2.64\times 10^{20}\,L\right)=(3.5\times 2.64)\times 10^{(-2+20)}\,kg\\\\=\bf{9.24\times 10^{18}\,kg}

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