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2 years ago

If M is the midpoint of XY, find the coordinates of X if M(-3,-1) and Y(-8,6).

Mathematics

1 answer:

NeTakaya2 years ago

7 0

Answer:

(2, -8)

Step-by-step explanation:

The coordinates of M are the average of the coordinates of X and Y.

-3 = (x + -8) / 2

-1 = (y + 6) / 2

Solving:

x = 2

y = -8

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john withdrew $175.75 from his bank account. now he has $450.25 left in his account. what was the original balance in his accoun

Naddika [18.5K]

Answer:

$626

Step-by-step explanation:

450.25+175.75=626

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2 years ago

Felicia places a rectangular rug that measures 10 feet by 11 feet in a triangular room with a base of 30 feet and height of 22 f

arsen [322]

Answer:

1. Area of rectangular rug is $110 ft^{2}$

2. Area of triangular room is $330ft^{2}$

Step-by-step explanation:

This problem bothers on the mensuration of flat shapes, rectangle and triangle.

step one

let us start by solving for the area of the rectangular rug

given data

Area A = ?

Length l = 11 ft

Width w= 10 ft

we know that the area of a rectangle is expressed as

$Area=Length * Width$

substituting our given data we have

$Area= 11*10\\Area= 110 ft^{2}$

step two

let us solve for the area of the triangular room

given data

Area A = ?

base b = 30 ft

height h= 22 ft

we know that the area of a triangle is expressed as

$Area= \frac{1}{2} *base* height\\$

substituting our given data we have

$Area= \frac{1}{2} * 30* 22\\Area=\frac{660}{2} \\Area= 330 ft^{2}$

8 0

3 years ago

Please someone help. Giving brainliest!!

hammer [34]

Answer:

I am pretty sure the answer is 3. hope this helps

7 0

2 years ago

Read 2 more answers

A random sample of 31 charge sales showed a sample standard deviation of $50. a 90% confidence interval estimate of the populati

Marysya12 [62]

The $100(1-\alpha)\%$ confidence interval of a standard deviation is given by:

$\sqrt{ \frac{(n-1)s^2}{\chi^2_{1- \frac{\alpha}{2} } }} \leq\sigma\leq\sqrt{ \frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2} } }}$

Given a sample size of 31 charge sales, the degree of freedom is 30 and for 90% confidence interval,

$\chi^2_{1- \frac{\alpha}{2} }=43.773 \\ \\ \chi^2_{\frac{\alpha}{2} }=18.493$

Therefore, the 90% confidence interval for the standard deviation is given by

$\sqrt{ \frac{(31-1)50^2}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(31-1)50^2}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{(30)2500}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(30)2500}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{75000}{43.773 }} \leq\sigma\leq\sqrt{ \frac{75000}{18.493 }} \\ \\ \Rightarrow \sqrt{1713.38} \leq\sigma\leq \sqrt{4055.59} \\ \\ \Rightarrow41.4\leq\sigma\leq63.7$

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2 years ago

Which graph summarize a set of data using an interval scale?

nignag [31]

To summarize a set of data using an interval scale, you would use a box plot.

8 0

3 years ago