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dlinn [17]
2 years ago
7

24÷2081 help me find the answer please and thank you

Mathematics
1 answer:
Leni [432]2 years ago
8 0

Answer:

= 86.7083333333

Welcome

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Can a triangle have sides of length 4,7,11?
Lesechka [4]

Answer:

No because 16+49 does not equal 121.

Step-by-step explanation:

first make 11 the hypotenuse and 4 and 7 side b and A

Use the pythagorean theorem: A^2+B^2=C^2

4^2+7^2=11^2

16+49=121

6 0
3 years ago
Find the equation of the line specified. The line passes through the points ( 5, 2) and ( 6, 4) a. y = 2x - 8 c. y = 2x + 12 b.
o-na [289]
<span>( 5, 2) and ( 6, 4)
slope m = (4-2)/(6-5) = 2

y = mx + b
b = y - mx
b = 2 - 2(5)
b = 2 - 10
b = -8

so now you have slope m = 2 and y intercept b = -8

equation
y = 2x - 8

answer
</span><span>a. y = 2x - 8</span>
4 0
3 years ago
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A right triangle has an area of 50 square inches. If the triangle is an isosceles triangle, what are the lengths of the legs of
Fed [463]
<span>If this is an isosceles triangle, then it has two 45 degree angles corresponding to two legs of equal length.  Orient the base of this triangle so that it's horizontal, and represent its length by b.  Let h represent the height of the triangle.  Then the area of this right triangle is 50 square inches = (1/2)(b)(h), or A = (b/2)h = 50 in^2.   

Due to the 45 degree angles, the height of this triangle is equal to half the base, or h = b/2.  Thus, (b/2)h = 50 becomes (b/2)(b/2) = 50, or b^2=200. Thus, b = 10sqrt(2), and h=(1/2)(10 sqrt(2)), or h = 5sqrt(2).

The length of one of the legs is the sqrt of  [5sqrt(2)]^2+[5sqrt(2)]^2, or

sqrt(25(2)+25(2)) = sqrt(100) = 10.



</span>
4 0
3 years ago
Can you help me anyone with this answer and I will do in return by marking you as a brainliest answer so plz plz plz help me.(RE
Murrr4er [49]
The price for each cd equals 9.95 so I would estimate it to 10$
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3 years ago
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Which statement is true about this argument?
Scilla [17]
D is the answer to this
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2 years ago
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