3 years ago

Fill in the missing terms of the arithmetic sequence, -7. 1,5-13

Mathematics

1 answer:

LenKa [72]3 years ago

7 0

Answer:

-3, 9

Step-by-step explanation:

The constant is 4.

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Answer:

Mean = 15.15

Standard deviation = 0.6062

Step-by-step explanation:

We are given a uniform distribution of quantity to be put in each bag.

Low and high filling weights:

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b) Standard Deviation:

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2 years ago

If y varies directly with x and y = 87 when x = 3, find y when x = 5. Write and solve a direct variation equation to find the an

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Answer:

145

Step-by-step explanation:

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y= 145

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2 years ago

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3 years ago

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10. Simplify the rational expression by rationalizing the denominator. 3 sqrt 160/sqrt 1350x A) 2 sqrt 15x/15x B) 3 sqrt 160/135

Viefleur [7K]

The simplified expression by rationalizing the denominator is (C) $\frac{4 \sqrt{15x} }{15x}$ .

First we must simplify the expression:
$\frac{3 \sqrt{160} }{\sqrt{1350x} } = \frac{12 \sqrt{10} }{15 \sqrt{6x} } = \frac{4 \sqrt{10} }{5 \sqrt{6x} }$

Then we factor the rational parts and cancel it out:
$\frac{4 \sqrt{2} \sqrt{5} }{5 \sqrt{2} \sqrt{3x} } = \frac{4\sqrt{5} }{5\sqrt{3x} }$

Then we rationalize the expression:
$\frac{4\sqrt{5} }{5\sqrt{3x} } * \frac{\sqrt{3x} }{\sqrt{3x} } = \frac{4 \sqrt{15x} }{5*3x} = \frac{4 \sqrt{15x} }{15x}$

<span>Finally, the simplified expression by rationalizing the denominator is (C) $\frac{4 \sqrt{15x} }{15x}$ .</span>

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3 years ago

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