Question

A sporting goods store received an order of 80 baseball caps, of which 12 were green. If 1 of the 80 caps is selected at random, what is the probability it will NOT be green?

Answer 1

Answer: $\frac{17}{20}$

Step-by-step explanation:

Given: The total number of caps = 80

The number of green caps = 12

Then , the number of caps which are not green = $80-12=68$

If 1 of the 80 caps is selected at random, what is the probability it will NOT be green is given by :-

$\text{P(Not green)}=\frac{\text{Caps not green}}{\text{Total caps}}\\\\\Rightarrow\ \text{P(Not green)}=\frac{68}{80}=\frac{17}{20}$

Hence, the probability it will NOT be green $=\frac{17}{20}$

Answer 2

Probabilit is positive events / total number of events

In this case the positive events is to pick a cap that is not green and the total number is 80 (the number of caps).

The number of not green caps is 80 - 12 = 68.

Then the probability the cap selected will not be green is 68 / 80 = 17 / 20