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AfilCa [17]
3 years ago
8

A sporting goods store received an order of 80 baseball caps, of which 12 were green. If 1 of the 80 caps is selected at random,

what is the probability it will NOT be green?
Mathematics
2 answers:
mamaluj [8]3 years ago
7 0

Answer: \frac{17}{20}

Step-by-step explanation:

Given: The total number of caps = 80

The number of green caps = 12

Then , the number of caps which are not green = 80-12=68

If 1 of the 80 caps is selected at random, what is the probability it will NOT be green is given by :-

\text{P(Not green)}=\frac{\text{Caps not green}}{\text{Total caps}}\\\\\Rightarrow\ \text{P(Not green)}=\frac{68}{80}=\frac{17}{20}

Hence, the probability it will NOT be green =\frac{17}{20}

Margaret [11]3 years ago
6 0
Probabilit is positive events / total number of events

In this case the positive events is to pick a cap that is not green and the total number is 80 (the number of caps).

The number of not green caps is 80 - 12 = 68.

Then the probability the cap selected will not be green is 68 / 80 = 17 / 20


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