Question

Ryan bought 3 books and a magazine . He paid $30 and relieved $5 change if the magazine cost twice as much as each book, find the cost of the magazine.
please explain in algebra only :)​

Answer 1

The books are $5, and the magazines are $10. I’m not sure which way you want it explained but since magazines are twice the price of books, you can solve the equation 3b + 2b = 25. This gives you b=5 which you just multiply by 2 giving you the price of a magazine.

Answer 2

Answer:  The required cost of the magazine is $10.

Step-by-step explanation:  Given that Ryan bought 3 books and a magazine. He paid $30 and relieved $5 change and the magazine cost twice as much as each book.

We are to find the cost of the magazine.

Let x and y represents the cost of a book and the magazine respectively.

Then, according to the given information, we have

$3x+y=30-5\\\\\Rightarrow 3x+y=25~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

and

$y=2x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

Substituting the value of y from equation (ii) in equation (i), we get

$3x+2x=25\\\\\Rightarrow 5x=25\\\\\Rightarrow x=\dfrac{25}{5}\\\\\Rightarrow x=5$

and from equation (ii), we get

$y=2\times5=10.$

Thus, the required cost of the magazine is $10.