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3 years ago

(16÷4)+((12+2)+6)order of operations show ur work please

Mathematics

1 answer:

GREYUIT [131]3 years ago

3 0

Order of operations or pedmas. parenthesis first

4+14+6= 24

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The geometric sequence that tells the perimeter of each stage in the building of Koch's snowflake has a first term of 3 and a ra

kari74 [83]

An = a1 * r^(n-1)
n = term to find = 18
a1 = first term = 3
r = common ratio = 4/3
now we sub

a18 = 3 * 4/3^(18 - 1)
a18 = 3 * 4/3^17
a18 = 3 * 133
a18 = 399

4 0

3 years ago

After arianna completed some work, she figured she still had 78 21/100 pictures to paint. if she completed another 34 23/25 pict

dezoksy [38]

Subtract the number she completed from what she had left to paint originally.

The fractions have different denominators so first step is to rewrite the fractions with a common denominator.

23/25 can be rewritten as 92/100

Now you have 78 21/100 - 34 92/100

Because 21/100 is smaller than 92/100 subtract 1 whole number from 78 and rewrite 1 as 100/100 and add that to the fraction.

78 21/100 becomes 77 121/100

Now subtract :

77 121/100 - 34 92/100

77-34 = 43

And 121/100 - 92/100 = 29/100

Combine to get 43 and 29/100

3 0

3 years ago

Prove that a triangle with the sides a - 1 cm to root under a

vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm

Hence,

${AB}^2 = (a -1)^2$

Now We know that

$(a- b)^2 = a^2+b^2 - 2ab$

So;

${AB}^2= a^2 + 1^2 -2\times a \times1$

${AB}^2 = a^2 + 1 -2a$

Now;

${BC}^2 = (2\sqrt{a})^2= 4a$

Also;

${CA}^2 = (a + 1)^2$

Now We know that

$(a+ b)^2 = a^2+b^2 + 2ab$

${CA}^2= a^2 + 1^2 +2\times a \times1$

${CA}^2 = a^2 + 1 +2a$

${CA}^2 = AB^2 + BC^2$

[By Pythagoras theorem]

$a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a$

Hence, ${CA}^2 = AB^2 + BC^2$

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

4 0

3 years ago

ILL MARK BRAINIEST IF YOU DO THIS CORRECTLY!!!

ehidna [41]

Answer:

76 percent done.

Step-by-step explanation:

Reasoning for this if its 76/100 you know that it will be 76. Or im Just got confused.

7 0

2 years ago

Solve the algebraic expression below (2/5) (10) + 8

Andrews [41]

Answer: 12.

Step-by-step explanation:

4 0

2 years ago