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Flauer [41]
3 years ago
11

(16÷4)+((12+2)+6)order of operations show ur work please

Mathematics
1 answer:
GREYUIT [131]3 years ago
3 0
Order of operations or pedmas. parenthesis first

4+14+6= 24
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The volume of a triangular prism is 20 cubic mm. If the dimensions were doubled, what would the new
anygoal [31]

Answer:

The new volume will be 160 mm^3

Step-by-step explanation:

The volume of a triangular prism can be calculated by multiplying the area of the triangular base by the height.

Let’s say we have the base with dimensions a and b, while the height can be h

The volume can be calculated as

V = 1/2 * a * b * h

Now , to answer this question, we shall be choosing arbitrary lengths for a, b and h. Whatever length we shall be choosing , we should make sure that they must be equal to 20 mm^3.

Let’s say we have a as 2mm , b as 4 mm and H as 5 mm

Plugging these into the equation, we surely have our volume as 20 mm^3

Now let’s double these dimensions. Our new dimensions become , 4mm by 8mm by 10mm

Plugging these new values into the equation, we have;

1/2 * 4 * 8 * 10 = 160 mm^3

Thus, our volume is expected to be increased by a factor of 8

7 0
3 years ago
Pls help me out<br> 4x - 10 = -6
kvv77 [185]

Answer: x = 1

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
What is the value of -3mn + 4m - 3 when m = 2 and n = -4?
grandymaker [24]
-3(2)(-4)+4(2)-3=24+8-3=29

The value is 29
4 0
3 years ago
Read 2 more answers
Can someone help me
xeze [42]
B is the answer i had this on my test the other day
8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cbegin%7Bequation%7D%5Ctext%20%7B%20Question%3A%20Find%20the%20value%20of%20%7D%20%5Cfrac%7B
ankoles [38]

\bold{Heya!}

Your answer to this is:

\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}

<h2>→ <u>EXPLANATION :-</u></h2>

<u />

<u />\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: (1)

\sf{Apply \: rule:} \: (a) = a

\sf{(1) = 1

\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: ^. \: 1

\sf{\frac{1}{1 \: + \:1} = \frac{1}{2}

\sf{\frac{2^1^0^0}{1 \: + \: x^2^0^0} ^.^ \: 1 \: = \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}

\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}

Hopefully This Helps ! ~

#LearnWithBrainly

\underline{Answer :}

<em>Jaceysan ~</em>

7 0
2 years ago
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