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3 years ago

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Find the slope of the line through (–9, –10) and (–2, –5). A. –five-sevenths B. seven-fifths C. five-sevenths D. –negative seven

-fifths (please help much aprecciated)

1 answer:

vredina [299]3 years ago

8 0

Answer:

C 5/7

Step-by-step explanation:

We can find the slope of a line using

m = (y2-y1)/(x2-x1)

= (-5 - -10) /(-2 - -9)

= (-5 +10)/(-2+9)

5/7

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How do I fill in the percentages?

ra1l [238]

<em>All Answers Under </em><em>Other Answers:</em>

Explanation:

First, you need to add all of the numbers to find the total budget. The total budget is <u>$1,116.</u> Then, to find the percentages, you need to divide each sections' money by the budget. For example, for 'contributions', you will do $175.76/$1,116 and get 0.157. But, this is a decimal. To make it into a percentage, you move the decimal point 2 spaces to the right. .157 = 15.7% So, for the 'contributions' section, the answer is 15.7%. Another example. For the 'housing' section, the amount was $350.84. Divide that by $1,116.

$\frac{350.84}{1,116}=0.314$

Move the decimal point <em>2 spaces to the right</em> -- 31.4%

<u>I hope you understand how I got these answers</u>

<em>Other Answers:</em>

Transportation: 4.5%

Clothing: 2.7%

Medical Expenses: 3.1%

Food: 17.9%

Taxes: 9.5%

Miscellaneous: 15.1%

8 0

3 years ago

Thaddeus models the number of hours of daylight in his town as

AfilCa [17]

Option (A) : least: 10 hours; greatest: 14 hours

The function f(x) = sin x has all real numbers in its domain, but its range is

−1 ≤ sin x ≤ 1.

How to solve such range questions?

Such questions in which every term is in addition and its range is asked is simplest ones to solve if we know the range of each of term. This can be seen from this question

Given: d(t) = 2sin(xt) + 12

= −1 ≤ sin (xt) ≤ 1.

= −2≤ 2 sin (xt) ≤ 2.

= 10 ≤ 2sin (xt) + 12 ≤ 14

= 10 ≤d(t) ≤ 14

Thus least: 10 hours; greatest: 14 hours

Learn more about range of trigonometric ratios here :

brainly.com/question/14304883

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6 0

2 years ago

How do you find the domain and range of a function and write it in set notation? What is the process of finding it? Tips and tri

DerKrebs [107]

Answer:

Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis

Step-by-step explanation:

plz forgive me if my answer is wrong

7 0

3 years ago

Read 2 more answers

Iteru [2.4K]

Answer:

28.574

Step-by-step explanation:

18.2 x 3.14 then divied by 2

6 0

3 years ago

Read 2 more answers

The top and bottom margins of a poster 66 cm each, and the side margins are 44 cm each. If the area of the printed material on t

jasenka [17]

Answer:

width: 24 cm
height: 36 cm

Step-by-step explanation:

When margins are involved, the smallest area will be the one that has its dimensions in the same proportion as the margins. If x is the "multiplier", the dimensions of the printed area are ...

(4x)(6x) = 384 cm^2

x^2 = 16 cm^2 . . . . . divide by 24

x = 4 cm

The printed area is 4x by 6x, so is 16 cm by 24 cm. With the margins added, the smallest poster will be ...

24 cm by 36 cm

_____

<em>Comment on margins</em>

It should be obvious that if both side margins are 4 cm, then the width of the poster is 8 cm more than the printed width. Similarly, the 6 cm top and bottom margins make the height of the poster 12 cm more than the height of the printed area.

_____

<em>Alternate solution</em>

Let w represent the width of the printed area. Then the printed height is 384/w, and the total poster area is ...

A = (w+8)(384/w +12) = 384 +12w +3072/w +96

Differentiating with respect to w gives ...

A' = 12 -3072/w^2

Setting this to zero and solving for w gives ...

w = √(3072/12) = 16 . . . . matches above solution.

__

<em>Generic solution</em>

If we let s and t represent the side and top margins, and we use "a" for the printed area, then the above equation becomes the symbolic equation ...

A = (w +s)(a/w +t)

A' = t - sa/w^2

For A' = 0, ...

w = √(sa/t)

and the height is ...

a/w = a/√(sa/t) = √(ta/s)

Then the ratio of width to height is ...

w/(a/w) = w^2/a = (sa/t)/a

width/height = s/t . . . . . . the premise we started with, above

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3 years ago