1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Taya2010 [7]
3 years ago
5

Suppose that, in 1995, the weight of 16-year old males in the United States was normally distributed with a mean of 143 lbs and

standard deviation equal to 15 lbs. Suppose that Roger, a public health researcher, believes that the popularity of video and computer gaming has made teenagers less active, and predicts that 16-year old males today weigh more than 16-year old males did in 1995. To test the theory, he chooses a random sample of 50 16-year old males and records their weights. The average weight of the sample is 147 lbs. Roger uses a z ‑ test to test the hypothesis that the average weight of 16-year old males has increased. He calculates the z ‑ statistic as 1.89 standard deviations above the mean. Use this standard normal z-distribution table to calculate the p-value of this statistic. Give your answer as a decimal rounded to four places. Also how to determin if this is a one-sided or two-sided test?
Mathematics
1 answer:
seropon [69]3 years ago
4 0

Answer:

Step-by-step explanation:

The null hypothesis is:

H0: μ(1995)=μ(2019)

The alternative hypothesis is:

H1: μ(1995)<μ(2019)

Because Roger wants to know if mean weight of 16-old males in 2019 is more than the mean weight of 16-old males in 1995 the test only uses one tail of the z-distribution.  It is not a  two-sided test because in that case the alternative hypothesis would be:  μ(1995)≠μ(2019).

To know the p-value, we use the z-statistic, in this case 1.89 and the significance level. Because the problem does not specify it, we will search for the p-value at a 5% significance level and at a 1%.

For a z of 1.89 and 5% significance level, the p-value is: 0.9744

For a z of 1.89 and 1% significance level, the p-value is: 0.9719

You might be interested in
Rewrite 2/5 + 5/12 with a common denominator.
RoseWind [281]

Answer:60 is the common denominator

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
I need help the correct answer please
madam [21]
7<span>x^4y^6 - Selection 3 is correct!</span>
5 0
3 years ago
Read 2 more answers
What is 1,000 to the power of 4?
quester [9]
The answer to what is 1,000 to the power of 4 is 1,000,000
8 0
3 years ago
Calculate the area and the circumference of the circle
tiny-mole [99]

Circumference = 2 x radius x Pi

Circumference = 2 x 0.8 x pi

Circumference = 1.6pi or 5.024 yards


area = r^2 x pi

Area = 0.8^2 x pi

Area = 0.64pi or 2.0096 square yards

6 0
2 years ago
Read 2 more answers
125 invitations to 75 Invitations ( Round To The Nearest Tenth Of A Percent If Necessary )
aleksklad [387]
I think the answer to this is .6 or 1.7

8 0
3 years ago
Other questions:
  • Alex wrote the equation C= 2n describe a situation that this equation could represent
    15·1 answer
  • Which rule describe the linear function for the graph?(Hint:You can graph points for each equation.)
    11·2 answers
  • The line PQ has equation 3x – 2y = 12. P is a point with coordinates (6, 3) and Q is the point
    14·1 answer
  • If the area A of a triangle is 60sq m (square meters) and the base b is 20m (meters) what is the altitude of h
    10·1 answer
  • A box filled with many different color crayons there are 40 white crayons 24 green crayons 12 red crayons 24 golden crayons and
    12·1 answer
  • Dawn enjoys exercising on the hiking trail by her house. She ran 2/5 of
    5·1 answer
  • Write in y=mx+b form
    11·1 answer
  • I’ll give brainliest!!! i just need the coordinates of T
    15·1 answer
  • Solve for x if 5 - x = 6<br><br> A) 1<br> B) No solution <br> C) -1<br> D) 5
    10·2 answers
  • Pls help. I’m having trouble with this last question
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!