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2 years ago

Can someone please help with the last problem

Mathematics

1 answer:

Brut [27]2 years ago

3 0

Answer:

18x +9h

Step-by-step explanation:

Such problems are tedious, but not difficult. The trick is to avoid making mistakes in the algebra.

$\dfrac{f(x+h)-f(x)}{h}=\dfrac{(9(x+h)^2)-(9x^2)}{h}\\\\=\dfrac{9(x^2+2xh+h^2)-9x^2}{h}=\dfrac{18xh+9h^2}{h}=\boxed{18x+9h}$

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3 years ago

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2x-2+3x

Step-by-step explanation:

2x-2+3x

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A= [2, 3; 2, 1], B=[3; 5]. Find AB & BA if possible

oksano4ka [1.4K]

Answer:

The value of AB is $\left[\begin{array}{ccc}21\\11\end{array}\right]$ and it's not possible to multiply BA.

Step-by-step explanation:

Consider the provided matrices.

$A=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right]$ , $B=\left[\begin{array}{ccc}3\\5\end{array}\right]$

Two matrices can be multiplied if and only if first matrix has an order m × n and second matrix has an order n × v.

Multiply AB

Matrix A has order 2 × 2 and matrix B has order 2 × 1. So according to rule we can multiply both the matrix as shown:

$AB=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right] \left[\begin{array}{ccc}3\\5\end{array}\right]$

$AB=\left[\begin{array}{ccc}2\times 3+3\times 5\\2\times 3+1\times 5\end{array}\right]$

$AB=\left[\begin{array}{ccc}6+15\\6+5\end{array}\right]$

$AB=\left[\begin{array}{ccc}21\\11\end{array}\right]$

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3 years ago

What is the derivative of w=(t^2+1)^100 How is it 200t(t^2+1)^99?

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USE CHAIN RULE

Outside first (using power rule)

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