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lions [1.4K]
2 years ago
12

Can someone please help with the last problem

Mathematics
1 answer:
Brut [27]2 years ago
3 0

Answer:

  18x +9h

Step-by-step explanation:

Such problems are tedious, but not difficult. The trick is to avoid making mistakes in the algebra.

  \dfrac{f(x+h)-f(x)}{h}=\dfrac{(9(x+h)^2)-(9x^2)}{h}\\\\=\dfrac{9(x^2+2xh+h^2)-9x^2}{h}=\dfrac{18xh+9h^2}{h}=\boxed{18x+9h}

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\sf{Given : 3tanx + 7 = \dfrac{2}{(1 - sinx)(1 + sinx)}}

We know that : (a - b)(a + b) = a² - b²

\implies \sf{3tanx + 7 = \dfrac{2}{1 - sin^2x}}

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\sf{\bigstar \ \ We \ know \ that : \boxed{\sf{\dfrac{1}{cos^2x} = sec^2x}}}

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