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satela [25.4K]
3 years ago
6

Pythagorean triples are given by the formulas x2 - y2, 2xy, and x2 + y2. Use the formulas for the Pythagorean triples to prove w

hy it is not possible for a right triangle to have legs with lengths of 16 and an odd number. Show all of your work for full credit.
Mathematics
1 answer:
erik [133]3 years ago
5 0
Let k be an integer. Suppose there is a triangle with legs of length 16 and 2k+1. Then by the Pythagorean theorem, the length of the hypotenuse should be

\sqrt{16^2+(2k+1)^2}=\sqrt{4k^2+4k+257}

The formulas for Pythagorean triples say that if the legs are integers, then so must be the hypotenuse, because if x=16 and y=2k+1 are integers, then so are x^2-y^2, 2xy, and x^2+y^2.

However, 4k^2+4k+257 is not a perfect square trinomial, which means for any integer k, the length of the hypotenuse is not an integer, so such a triangle doesn't exist.
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3 years ago
Evaluate <br> (-315) ×4<br> with the correct explaination
Naya [18.7K]

\Large\textsf{\textbf{Answer\::}}

-1, 260

\large\textsf{\textbf{Calculations\;:}}

First , take a look at the signs of the numbers we're asked to multiply .

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\footnotesize\text{hope\:helpful~}

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