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Bond [772]
3 years ago
13

hypothesis that there is a relationship between parents’ and children’s party identification. Would we be correct in inferring t

hat such a relationship also exists in the population? Explain your answer. What is the probability that any relationship we found is due to pure chance?
Mathematics
1 answer:
lorasvet [3.4K]3 years ago
3 0

Answer:

No

It could be purely due to chance.

Step-by-step explanation:

A population is defined as the whole group which has the same characteristics. For example a population of the college belongs to the same college . But a sample may be an element of a population.

So it is not necessary for a population to have the same characteristics as the sample.

But it is essential for the sample to have at least one same characteristics as the population.

So we would not be correct in inferring that such a relationship also exists in the population.

It is a hypothesis which can be true or false due to certain conditions or limitations as the case maybe.

For example in a population of smokers some may be in the habit of taking cocaine. But a sample of cocaine users does not mean the whole population uses it.

It could be purely due to chance if we find out that there is a relationship between parents’ and children’s party identification in the population.

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In the first term, we will have just 8 left since everything else in the term is factored out.

The second term has a 7m^4n^3 left. Notice that both of these terms no longer have a negative sign since the negative was factored out.

The answer is (-m^2n)(8+7m^4n^3)
8 0
3 years ago
Why do we need to construct table in getting POPULATION VARIANCE?
son4ous [18]

Answer:

it's helps it by standing

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2 years ago
Simulate the rolling of two dice 10,000 times. (b) Identify which rolls of the dice are in the event A, the dice add up to a per
dexar [7]

Answer:

Answer explained below

Step-by-step explanation:

(a)

Simulate the rolling of two dice 10,000 times D1 and D2 are the 10,000 results of roll of dice 1 and dice 2.

D1 = sample(c(1:6), 10000, replace = TRUE)

D2 = sample(c(1:6), 10000, replace = TRUE)

Sum = D1 + D2

(b)

The event A, the dice add up to a perfect square (4 or 9).

A = Sum[Sum == 4 | Sum ==9]

Proportion of A, P(A) = 0.189

length(A) / length(Sum)

(c)

The event B, the dice add up to an even number.

B = Sum[Sum %% 2 == 0]

Proportion of B, P(B) = 0.5049

length(B) / length(Sum)

(d)

The  rolls are in A ∩ B (common to both A and B)

> intersect(A,B)

[1] 4

The proportion that are in A ∩ B is 0.0792

length(Sum[Sum == 4]) / length(Sum)

P(A) * P(B) = 0.189 * 0.5049 = 0.0954

The proportion in A multiplied by the proportion that are in B is not equal to P(A ∩ B)

(e)

Of the rolls in which B occurs, the proportion of those rolls are also in A is 0.4190476

length(Sum[Sum == 4]) / length(A)

This proportion is greater than the P(A) calculated in part (b).

4 0
3 years ago
Carla buys a dress for $20.00 she pays 7 percent sales tax .. How much does she pay for the dress with tax?
BaLLatris [955]

Answer:

Carla pays $21.4 for the dress with tax.

Step-by-step explanation:

Here we are given that :

Price of dress = $20

Sales tax = 7%

Price of dress with tax = $20 + 7% of 20

Price of dress with tax = 20+1.4 = 21.4

Price of dress with tax = $21.4

Carla pays $21.4 for the dress with tax.

4 0
3 years ago
Please help multiple choice !!
professor190 [17]
The answer is x= 2, y= 1
8 0
2 years ago
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