1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mekhanik [1.2K]
3 years ago
5

The graph of a system of equations will intersect at more than one point?

Mathematics
1 answer:
Bess [88]3 years ago
6 0
I believe the answer is sometimes
You might be interested in
3. Jim bought 2 books yesterday. The price
natima [27]

Answer:

26.40 divided by 2 is 13.20 13.20 is your answer!

7 0
3 years ago
Plz help will make brainlyist
siniylev [52]

Answer:

A. 6

B. 143

C. The words "less than", "equal to", and "no more than"

Step-by-step explanation:

For a, we would want to first make an equation to represent the problem. It appears you've already figured that out though, so lets solve it!

Subtract 56 on both sides.

-6m=-36

Now divide -36 by -6 to isolate m.

m=6

It will take her 6 minutes.

For B, we need to make another equation.

2.95b<450-28

First, we can subtract 28 from the total, because she has already spent $28.

Now our equation is 2.95b<422

Lastly, just divide both sides by 2.95 to isolate b.

Our solution is 143. So she can buy 143 batteries.

Lastly, for 13, we can say that the words "less than", "equal to" and "no more than" can indicate an inequality in a real word problem.

Hope this helps!

3 0
3 years ago
WHO WANTS BRAINLIEST?
kogti [31]
3(4x +12)=180
12x + 36 =180
-36. -36
180-36= 144
12x = 144
——. ——-
12. 12
X = 12
6 0
3 years ago
Cos ( α ) = √ 6/ 6 and sin ( β ) = √ 2/4 . Find tan ( α − β )
Zina [86]

Answer:

\purple{ \bold{ \tan( \alpha  -  \beta ) = 1.00701798}}

Step-by-step explanation:

\cos( \alpha ) =  \frac{ \sqrt{6} }{6}  =  \frac{1}{ \sqrt{6} }  \\  \\  \therefore \:  \sin( \alpha )  =  \sqrt{1 -  { \cos}^{2} ( \alpha ) }  \\  \\  =  \sqrt{1 -  \bigg( {\frac{1}{ \sqrt{6} } \bigg )}^{2} }  \\  \\ =  \sqrt{1 -  {\frac{1}{ {6} }}}  \\  \\ =  \sqrt{ {\frac{6 - 1}{ {6} }}}   \\  \\  \red{\sin( \alpha ) =  \sqrt{ { \frac{5}{ {6} }}} } \\  \\  \tan( \alpha ) =  \frac{\sin( \alpha ) }{\cos( \alpha ) }  =  \sqrt{5}  \\  \\ \sin( \beta )  =  \frac{ \sqrt{2} }{4}  \\  \\  \implies \: \cos( \beta )  =   \sqrt{ \frac{7}{8} }  \\  \\ \tan( \beta )  =  \frac{\sin( \beta ) }{\cos( \beta ) } =  \frac{1}{ \sqrt{7} }   \\  \\  \tan( \alpha  -  \beta ) =  \frac{ \tan \alpha  -  \tan \beta }{1 +  \tan \alpha .  \tan \beta}  \\  \\  =  \frac{ \sqrt{5} -  \frac{1}{ \sqrt{7} }  }{1 +  \sqrt{5} . \frac{1}{ \sqrt{7} } }  \\  \\  =  \frac{ \sqrt{35} - 1 }{ \sqrt{7}  +  \sqrt{5} }  \\  \\  \purple{ \bold{ \tan( \alpha  -  \beta ) = 1.00701798}}

8 0
3 years ago
A number is chosen at random from 1 to 25. Find the probability of selecting an odd number or multiples of 5. *
Ymorist [56]

Answer:

Odd number: 13/25 (52%)

Multiples of 5: 5/25 (20%)

Step-by-step explanation:

There are 13 odd numbers between 1 and 25 so you have a 13/25 chance which is 52% (13/25 = 0.52). There are 5 multiples of 2 between 1 and 25 so you have a 5/25 chance which is 20% (5/25 = 0.2).

8 0
3 years ago
Other questions:
  • I need help again please help
    6·1 answer
  • Product of 3a2b and 5a2–4ab + 2b2is
    9·1 answer
  • what is an equation of the line that passes through the point(-5,-5) and is parallel to the line 3x-5y=25​
    12·1 answer
  • Not sure if i got these right can someone check my work
    15·1 answer
  • I need help on this one please
    5·2 answers
  • The number of games, g, to be played with n teams can be written by the following equation: g=n^2-n if there are to be 132 games
    7·1 answer
  • Find the values of X and Y
    8·1 answer
  • Plz help me well mark brainliest if correct!!.....
    11·2 answers
  • Write an express for the perimeter of the figure shown by combing like terms.
    14·1 answer
  • FACTORIZE AND Split the middle term: 72 + b - b^2​
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!