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4 years ago

What is the S.I unit of torque?

1 answer:

4 0

Torque has the dimension of force times distance, symbolically L2MT−2. Official SI literature suggests using the unit newton metre (N⋅m), or, joule per radian (J/rad). The unit newton metre is properly denoted N⋅m rather than m.

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Which law relates to the ideal gas law?

professor190 [17]

Answer: The law that related the ideal gas law is $\frac{V_1}{n_1}=\frac{V_2}{n_2}$

Explanation:

There are 4 laws of gases:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature.

Mathematically,

$P_1V_1=P_2V_2$

Charles' Law: This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Gay-Lussac Law: This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

Avogadro's Law: This law states that volume is directly proportional to number of moles at constant temperature and pressure.

Mathematically,

$\frac{V_1}{n_1}=\frac{V_2}{n_2}$

Hence, the law that related the ideal gas law is $\frac{V_1}{n_1}=\frac{V_2}{n_2}$

8 0

4 years ago

Read 2 more answers

How many grams of glucose are needed to prepare 400. g of a 2.00% (m/m) glucose solution g?

Dominik [7]

The grams of glucose are needed to prepare 400g of a 2.00%(m/m) glucose solution g is calculated as below

=% m/m =mass of the solute/mass of the solution x100

let mass of solute be represented by y
mass of solution = 400 g
% (m/m) = 2% = 2/100

grams of glucose is therefore =2/100 = y/400
by cross multiplication

100y = 800
divide both side by 100

y= 8.0 grams

5 0

4 years ago

For each pair, which has higher potential energy?

Allushta [10]

Answer:

Maybe A)

Explanation:

Can you make me the Brainliest answer ?

7 0

3 years ago

The polyatomic nitrate ion (NO3−) is present in both the products and the reactants of the chemical equation shown below.

Diano4ka-milaya [45]

Answer:

There is one nitrate ion in the products, and two in the reactants of this equation.

Explanation:

1: We know a nitrate ion has the formula $NO_{3}^{-$ , so we just need to count how many of them are on each side of the equation.

2: To find how many are in the reactants of the equation, you look at the left hand side (before the arrow). You can see the section $(NO_{3} )_{2}$ , which shows that there are two nitrate ions in the reactant side (as seen by the little 2).

3: To find how many are on the products side, you do the same thing - this time there is only one $NO_{3}^{-$ in the lithium nitrate.

So, there is one nitrate ion in the products, and two in the reactants of this equation.

7 0

3 years ago

Read 2 more answers

Mercury (Hg) is present in trace amounts in coal, ranging from 50.0 to 200.0 ppb. A typical power plant burns 1.49 million tons

faust18 [17]

Answer and Explanation:

To calculate this, simply use an equality of proportions:

50 particles : 1 billion particles = x tons : 1.49 million tons

The value of x can be solved for by multiplying the ratio on the left by the value 1.49 million / 1 billion:

So, x = (50)(0.00149) tons = 0.0745 tons

Then, do the same thing for the larger concentration:

x = (200)(0.00149) tons = 0.298 tons

5 0

2 years ago