Answer:
The answer to your question is given below
Explanation:
The balanced equation for the reaction is given below:
CaO(s) + CH4(g) + 2H2O(g) <=> CaCO3(s) + 4H2(g)
1. Writing an expression for the equilibrium constant, K.
The equilibrium constant, K for a reaction is simply the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient.
Thus, we can write the equilibrium constant, K for the reaction as follow:
CaO(s) + CH4(g) + 2H2O(g) <=> CaCO3(s) + 4H2(g)
K = [CaCO3] [H2]⁴ / [CaO] [CH4] [H2O]²
2. Based on the value of K, more products will be in the equilibrium mixture since the value of K is a positive large number.
Answer:
Noble gases.
Good Luck & Have a good day!
(.❛ ᴗ ❛.)
Answer:
The solutions of hydrobromic acid and of chloric acid are the most electrically conductive.
Explanation:
The electrical conductivity of a solution is determined by the concentration of ions in the solution. The acids listed react with water to form ions. In the case of hydrobromic acid, for example, the reaction is as follows:
HBr + H2O >> H3O(+) + Br(-)
Hydrobromic acid and chloric acid are strong acids, meaning the reaction is considered to proceed at 100%. Acetic acid, however, is a weak acid and the reaction with water does not go to completion, so there are less ionic species in the solution of acetic acid, which makes it less electrically conductive.