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Nesterboy [21]
3 years ago
11

An elevator is 2/3 full. The people in the elevator weigh 1/3 ton altogether. How many tons can the elevator carry when it is co

mpletely full?
1/2 ton
2 ton
1 tons
1/6 ton​
Mathematics
1 answer:
dimulka [17.4K]3 years ago
6 0

Answer:

Half of a ton

Step-by-step explanation:

2/3 of the elevator are already full and the elevator already weighs 1/3 of ton.The elevator needs 1/3 more of people to make the elevator full so that would be half of 1/3 of a ton which is a sixth.So add 1/6 and 1/3 together ams you get 1/2.

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Answer:

296.693\leq x\leq 319.307

Step-by-step explanation:

The confidence interval for the population mean x can be calculated as:

x'-z_{\alpha /2}\frac{s}{\sqrt{n} } \leq x\leq x'+z_{\alpha /2}\frac{s}{\sqrt{n} }

Where x' is the sample mean, s is the population standard deviation, n is the sample size and z_{\alpha /2} is the z-score that let a proportion of \alpha /2 on the right tail.

\alpha is calculated as: 100%-99%=1%

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3 years ago
X-y=5 and x^2y=5x+6​
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By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.

<h3>How to solve a system of equations</h3>

In this question we have a system formed by a <em>linear</em> equation and a <em>non-linear</em> equation, both with no <em>trascendent</em> elements and whose solution can be found easily by algebraic handling:

x - y = 5      (1)

x² · y = 5 · x + 6       (2)

By (1):

y = x + 5

By substituting on (2):

x² · (x + 5) = 5 · x + 6

x³ + 5 · x² - 5 · x - 6 = 0

(x + 5.693) · (x - 1.430) · (x + 0.737) = 0

There are three solutions: x₁ ≈ 5.693, x₂ ≈ 1.430, x₃ ≈ - 0.737

And the y-values are found by evaluating on (1):

y = x + 5

x₁ ≈ 5.693

y₁ ≈ 10.693

x₂ ≈ 1.430

y₂ ≈ 6.430

x₃ ≈ - 0.737

y₃ ≈ 4.263

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To learn more on nonlinear equations: brainly.com/question/20242917

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