We are given two binomials: x+4 , x^2-9.
x+4 can't be factored. Therefore, it is a prime.
Let us work on x^2-9.
9 could be written as 3^2.
Therefore, x^2-9 = x^2 - 3^2.
Now, we can apply difference of the squares formula to factor it.
We know a^2 -b^2 = (a-b) (a+b).
Therefore, x^2 - 3^2 can be factored as (x-3) (x+3).
So, x^2-9 is not a prime binomial because it can be factored as (x-3) (x+3).
Answer:
B (r= 1/6s)
Step-by-step explanation:
If you just work out each option, you'll see that "s" multiplied by 1/6 gets r.
Answer:
-0.4 or 2.3
Step-by-step explanation:
simple
each box is 0.1 unit
Answer:
3a -2
Step-by-step explanation:
2-(-3a+4)
Distribute the minus sign to each term inside the parentheses
2 - -3a -4
2 + 3a -4
Combine like terms
2-4 +3a
-2 +3a
We usually put the variables first
3a -2
5x-9y=-65
10x-3y=20
Multiple the first equation by 2
10x-18y=-130
10x -3y=20
Then subtract the two equations to get rid of the x
21y=-150
Divide the -150 by 21
Y=-7.14
Plug the y into the original equation. (Either one)
5x-9(-7.14)=-65
5x-64.28=-65
Then add 64.28 to the -65
5x=-0.72
Divide by 5
X=-0.144
I hope this is right
