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monitta
3 years ago
5

Can You Help Me With numbers 6-8

Mathematics
1 answer:
k0ka [10]3 years ago
4 0

Hello,

Your answers and explanations are below.

6 - 5xy

5 times the product of x and y. The product of x and y means to multiply. That is where we get this: xy. 5 times that product is where we add 5 to it and get this: 5xy.


7 - 4x

We get this because we know he gets $4 an hour. We just do not know how many hours he babysat. The hours is X and we multiply that by 4.


8 - 5.5

Take 8.3 and subtract 2.8 to find x. Once we do that we get 5.5, and that is X.


9 - We can't see the problem. It's cut off

Good Luck,

- I.A. -

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The square root of 12 is irrational.<br><br> True<br> False
dalvyx [7]
True.

The square root of 12:   √12 = 3.464101......

This continues indefinitely and can not be represented as a ratio of two integers.

So it is not rational, that is irrational.
7 0
3 years ago
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Ben claims that the points (2. 4), (4, 8) and (8, 12) tie on a line. Show that Ben is incorrect.
NeX [460]
Find the slope(s) twice, first the slope of the line connecting (2,4) and (4,8) and then the slope of the line connecting (2,4) and (8,12).  If you get different slopes, then it'd be safe for you to conclude that the points do not lie on the same line.

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3 years ago
1. Prove or give a counterexample for the following statements: a) If ff: AA → BB is an injective function and bb ∈ BB, then |ff
Fantom [35]

Answer:

a) False. A = {1}, B = {1,2} f: A ⇒ B, f(1) = 1

b) True

c) True

d) B = {1}, A = N, f: N ⇒ {1}, f(x) = 1

Step-by-step explanation:

a) lets use A = {1}, B = {1,2} f: A ⇒ B, f(1) = 1. Here f is injective but 2 is an element of b and |f−¹({b})| = 0., not 1. This statement is False.

b) This is True. If  A were finite, then it can only be bijective with another finite set with equal cardinal, therefore, B should be finite (and with equal cardinal). If A were not finite but countable, then there should exist a bijection g: N ⇒ A, where N is the set of natural numbers. Note that f o g : N ⇒ B is a bijection because it is composition of bijections. This, B should be countable. This statement is True.

c) This is true, if f were surjective, then for every element of B there should exist an element a in A such that f(a) = b. This means that  f−¹({b}) has positive cardinal for each element b from B. since f⁻¹(b) ∩ f⁻¹(b') = ∅ for different elements b and b' (because an element of A cant return two different values with f). Therefore, each element of B can be assigned to a subset of A (f⁻¹(b)), with cardinal at least 1, this means that |B| ≤ |A|, and as a consequence, B is finite.

b) This is false, B = {1} is finite, A = N is infinite, however if f: N ⇒ {1}, f(x) = 1 for any natural number x, then f is surjective despite A not being finite.

4 0
3 years ago
Please Help me! Algebra 1
dem82 [27]

Option a: The number of bacteria at time x is 0.

Option b: An exponential function that represents the population is y=200(1.5)^x

Option c: The population after 10 minutes is 11534(app)

Explanation:

It is given that the coordinates of the graph are (0,200), (1,300) and (2, 450)

Option a: To determine the number of bacteria x when y = 200

From the graph, we can see that the line meets y = 200 when x = 0

Thus, the coordinates are (0,200)

Hence, the number of bacteria at time x is 0 when y = 200.

Option b: Now, we shall determine the exponential function of the population.

The general formula for exponential function is y=a \cdot b^{x}

Where a is the starting point and a=200

b is the common difference.

To determine the common difference, let us divide,

\frac{300}{200} =1.5

Also, \frac{450}{300} =1.5

Hence, the common difference is b=1.5

Thus, substituting the values a=200 and b=1.5 in the formula y=a \cdot b^{x},

we have, y=200(1.5)^x

Hence, An exponential function that represents the population is y=200(1.5)^x

Option c: To determine the population after 10 minutes, let us substitute x=10 in y=200(1.5)^x, since the x represents the population of the bacteria in minutes.

Thus, we have,

\begin{aligned}y &=200(1.5)^{x} \\&=200(1.5)^{10} \\&=200(57.67) \\&=11534\end{aligned}

Hence, the population after 10 minutes is 11534(app)

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Isaac's hair was 12 centimeters long after his last haircut, and it grows 8 centimeters every year. Isaac last got his hair cut
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Answer:

76

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1.) 8 x 8 =64

2.) 12 + 64 =76

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