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True [87]
3 years ago
5

Patrick added 1/4 teaspoons of cayenne pepper and 1/3 teaspoons of black pepper to his enchilada sauce. What is the total amount

of the two spices that Patrick added to his sauce?​
Mathematics
1 answer:
maw [93]3 years ago
6 0

Answer:

7/12

Step-by-step explanation:

You first make a common denominator. You make both the denominators 12, then make one numerator 3 and another numerator 4. Now you have an easy equation; 3/12 + 4/12, which equals to 7/12

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PLEASE HELP!!!!!
leva [86]

Answer:

11.7 units

Step-by-step explanation:

sq root(2--4)^2+(-7-3)^2

sq root(6)^2 + (-10)^2

sq root (36)+(100)

sq root 136

equals 11.66 which rounds up to 11.7

6 0
3 years ago
8. Bob bought a pair of tennis shoes on sale
mr_godi [17]

Answer:

20%

Step-by-step explanation:

So, I would set this up as a proportion-

72          x

90        100

Cross multiply-

100 x 72 = 7200

Divide-

7200/90 = 80

Subtract-

100 - 80 = 20

So, it is a 20% decrease

4 0
3 years ago
What is the distance between -25 to -12 on the number line
STatiana [176]

Answer:

120 units

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Convert 1 1/3 to a improper fraction
Morgarella [4.7K]

Answer:

3 2/3

Step-by-step explanation:

Divide 11 by 3 using long division method. then place the quotient as whole number and reminder as numerator and dividend as denominator

5 0
4 years ago
Each year, all final year students take a mathematics exam. It is hypothesised that the population mean score for this test is 1
Yuri [45]

Answer:

90% confidence interval for the population mean test score is [95.40 , 106.59]

Step-by-step explanation:

We are given that the population mean score for mathematics test is 115. It is known that the population standard deviation of test scores is 17.

Also, a random sample of 25 students take the exam. The mean score for this group is 101.

The, pivotal quantity for 90% confidence interval for the population mean test score is given by;

        P.Q. = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, X bar = sample mean = 101

              \sigma = population standard deviation

              n = sample size = 25

So, 90% confidence interval for the population mean test score, \mu is ;

P(-1.6449 < N(0,1) < 1.6449) = 0.90

P(-1.6449 < \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.6449) = 0.90

P(-1.6449 * \frac{\sigma}{\sqrt{n} } < {Xbar-\mu} < 1.6449 * \frac{\sigma}{\sqrt{n} } ) = 0.90

P(X bar - 1.6449 * \frac{\sigma}{\sqrt{n} } < \mu < X bar + 1.6449 * \frac{\sigma}{\sqrt{n} } ) = 0.90

90% confidence interval for \mu = [ X bar - 1.6449 * \frac{\sigma}{\sqrt{n} } , X bar + 1.6449 * \frac{\sigma}{\sqrt{n} } ]

                                                  = [ 101 - 1.6449 * \frac{17}{\sqrt{25} } , 10 + 1.6449 * \frac{17}{\sqrt{25} } ]

                                                  = [95.40 , 106.59]

Therefore, 90% confidence interval for the population mean test score is [95.40 , 106.59] .

7 0
4 years ago
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