All categories

3 years ago

Open-Ended Which of these situations can be represented by the opposite of 53? Use pencil and

Mathematics

1 answer:

Alexeev081 [22]3 years ago

7 0

Answer:

A book was 53 pages shorter than you expected

Jennifer sold 53 apples.

Andrew spent $53.

Step-by-step explanation:

The question proposed that we should determine which situation can be said to be the opposite of 53. From the listed option, we will realize that the following:

A book was 53 pages shorter than you expected

Jennifer sold 53 apples.

Andrew spent $53.

The above options are the opposite of 53. This is because a book that was shorter than expected will need to be refilled.

Suppose Jennifer has x apples, and She sold 53 apples out of it. It means x = -53, which is the opposite of 53.

Andrew spent $53; let say Andrew had y+$53. After spending $53, he has y = - $53, which is the opposite of 53.

But the temperature, which was 53°F, will still be at that position on the thermometer provided it is not being affected by external conditions.

You might be interested in

PLEASE ANSWER FAST!!!

8090 [49]

Answer:

There isnt a graph to see

6 0

3 years ago

Find the MAD of the data below:<br><br>52. 47. 65<br>43. 51<br>

djyliett [7]

Answer:

The answer is 5.52

6 0

3 years ago

Read 2 more answers

In Exercises 40-43, for what value(s) of k, if any, will the systems have (a) no solution, (b) a unique solution, and (c) infini

svet-max [94.6K]

Answer:

If k = −1 then the system has no solutions.

If k = 2 then the system has infinitely many solutions.

The system cannot have unique solution.

Step-by-step explanation:

We have the following system of equations

$x - 2y +3z = 2\\x + y + z = k\\2x - y + 4z = k^2$

The augmented matrix is

$\left[\begin{array}{cccc}1&-2&3&2\\1&1&1&k\\2&-1&4&k^2\end{array}\right]$

The reduction of this matrix to row-echelon form is outlined below.

$R_2\rightarrow R_2-R_1$

$\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\2&-1&4&k^2\end{array}\right]$

$R_3\rightarrow R_3-2R_1$

$\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&3&-2&k^2-4\end{array}\right]$

$R_3\rightarrow R_3-R_2$

$\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&0&0&k^2-k-2\end{array}\right]$

The last row determines, if there are solutions or not. To be consistent, we must have k such that

$k^2-k-2=0$

$\left(k+1\right)\left(k-2\right)=0\\k=-1,\:k=2$

Case k = −1:

$\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-1-2\\0&0&0&(-1)^2-(-1)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-3\\0&0&0&-2\end{array}\right]$

If k = −1 then the last equation becomes 0 = −2 which is impossible.Therefore, the system has no solutions.

Case k = 2:

$\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&2-2\\0&0&0&(2)^2-(2)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&0\\0&0&0&0\end{array}\right]$

This gives the infinite many solution.

5 0

3 years ago

How do I find the value of the missing sides and angles

Zarrin [17]

That is a 30 60 90 triangle.
Read about those here: http://www.1728.org/trig2.htm

4 0

3 years ago

6 points are placed on the line a , 4 points are placed on the line b . How many triangles is it possible to form such that thei

BaLLatris [955]

Answer:

Step-by-step explanation:

Using side b as the base, 4 points makes 3 bases (the space in between). With three bases, you can have 3 bases of 1 segment, 2 bases of 2 segments, and 1 base of 3 segments. This equals 6 bases. Each of these can connect to a point on line a. 6x6=36

Using side a as the base, 6 points makes 5 bases. With 5 bases, you can have 5 bases of 1 segment, 4 bases of 2 segments, 3 bases of 3 segments, 2 bases of 4 segments, and 1 base of 5 segments. This equals 15 bases. Each of these can connect to a point on line b. 15x4=60

36+60=96

5 0

3 years ago

Read 2 more answers