So, how far is the car from where it was at t = 0 is 40 m
<h3>Velocity of the car</h3>
Since the location x of the car in meters is given by the function x = 30t - 5t² where t is in seconds, we need to find the time at which its velocity is 10 m/s in the negative direction by differentiating x with respect to t to find its velocity, v.
So, v = dx/dt
= d(30t - 5t²)/dt
= d30t/dt - d5t²/dt
= 30 - 10t
When v is 10 m/s in the negative direction, v = -10 m/s.
So, v = 30 - 10t
-10 = 30 - 10t
-10 - 30 = -10t
-40 = -10t
t = -40/-10
t = 4 s
<h3>The distance at 4 s when its velocity is -10 m/s</h3>
Since at t = 4 s, its velocity is -10 m/s and x = 30t - 5t² is the car's location. The car's distance from t = 0 after its velocity is -10 m/s is
x(4) - x(0) = 30(4) - 5(4)² - [30(0) - 5(0)²]
= 120 - 5(16) - [0 - 0]
= 120 - 80 - 0
= 40 m
So, how far is the car from where it was at t = 0 is 40 m
Learn more about distance of car here:
brainly.com/question/17097458
Answer:
A) -2y + 2x >= 7x+y+5
Step-by-step explanation:
I can't remember how to get there by actually doing math, but I used a calculator on a program called Desmos (don't know if you've heard of it?). It's great because they have lots of types of calculators for any kind of math you're doing. I used the graphing calculator for this one. There's also a scientific calculator which I used a lot throughout middle school when we had to do operations with PEMDAS OR GEMS.
To find the graphing calculator for future problems like this, just type in Desmos Graphing Calculator and it should come up.
Hope you find it useful.
Answer:
The answer is B -5/18. you're welcome :)
Step-by-step explanation:
The sum is 8 wholes because if you add 3 and 2 you get 5 and the denominator stays the same so that becomes a whole and you add that 7 wholes plus the other 1 whole and you get 8
6 1/2 x 1 8/13
13/2 x 21/13 = 273/26 = 10 1/2
The answer is C, 10 1/2.
