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3 years ago

It takes 14 girls 48 minutes to finish painting a mural. How long would it take if only 4 girls painted the mural?

Mathematics

2 answers:

Oksi-84 [34.3K]3 years ago

8 0

Answer:

It woud take 4 girls 183 min. to complete a mural.

Step-by-step explanation: You multiply 48 x 4 and get 183

Wittaler [7]3 years ago

6 0

Answer:

It would take 13.7142857 or 13.7, in better terms about 14 minutes.

Step-by-step explanation:

48/14 = 3.42857143

3.42857143 x 4 = 13.7142857 or 13.7.

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Step-by-step explanation:

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The prior probabilities for events A1 and A2 are P(A1) = 0.20 and P(A2) = 0.80. It is also known that P(A1 ∩ A2) = 0. Suppose P(

Umnica [9.8K]

Answer:

(a) $A_1$ and $A_2$ are indeed mutually-exclusive.

(b) $\displaystyle P(A_1\; \cap \; B) = \frac{1}{20}$ , whereas $\displaystyle P(A_2\; \cap \; B) = \frac{1}{25}$ .

(d) $\displaystyle P(A_1 \; |\; B) \approx \frac{5}{9}$ , whereas $P(A_1 \; |\; B) = \displaystyle \frac{4}{9}$

Step-by-step explanation:

$P(A_1 \; \cap \; A_2) = 0$ means that it is impossible for events $A_1$ and $A_2$ to happen at the same time. Therefore, event $A_1$ and $A_2$ are mutually-exclusive.

By the definition of conditional probability:

$\displaystyle P(B \; | \; A_1) = \frac{P(B \; \cap \; A_1)}{P(B)} = \frac{P(A_1 \; \cap \; B)}{P(B)}$ .

Rearrange to obtain:

$\displaystyle P(A_1 \; \cap \; B) = P(B \; |\; A_1) \cdot P(A_1) = 0.25 \times 0.20 = \frac{1}{20}$ .

Similarly:

$\displaystyle P(A_2 \; \cap \; B) = P(B \; |\; A_2) \cdot P(A_2) = 0.80 \times 0.05 = \frac{1}{25}$ .

Note that:

$\begin{aligned}P(A_1 \; \cup \; A_2) &= P(A_1) + P(A_2) - P(A_1 \; \cap \; A_2) = 0.20 + 0.80 = 1\end{aligned}$ .

In other words, $A_1$ and $A_2$ are collectively-exhaustive. Since $A_1$ and $A_2$ are collectively-exhaustive and mutually-exclusive at the same time:

$\displaystyle P(B) = P(B \; \cap \; A_1) + P(B \; \cap \; A_2) = \frac{1}{20} + \frac{1}{25} = \frac{9}{100}$ .

By Bayes' Theorem:

$\begin{aligned} P(A_1 \; |\; B) &= \frac{P(B \; | \; A_1) \cdot P(A_1)}{P(B)} \\ &= \frac{0.25 \times 0.20}{9/100} = \frac{0.05 \times 100}{9} = \frac{5}{9}\end{aligned}$ .

Similarly:

$\begin{aligned} P(A_2 \; |\; B) &= \frac{P(B \; | \; A_2) \cdot P(A_2)}{P(B)} \\ &= \frac{0.05 \times 0.80}{9/100} = \frac{0.04 \times 100}{9} = \frac{4}{9}\end{aligned}$ .

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2 years ago

Determine whether each equation has one solution, no solution, or infinite solutions.

Sati [7]

Answer:

a. has one solution

b. infinite solution

Step-by-step explanation:

2(x - 1) + 6 = 4x - 22

2x - 2 + 6 = 4x - 22

2x - 4x = 2 - 6 - 22

-2x = -26

x = 26/2

x = 13

6(2x + 1) – 2 = 12x + 4

12x + 6 - 2 = 12x + 4

12x - 12x = 4 + 2 - 6

0 = 0

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3 years ago

Explain the following types of angles:

ZanzabumX [31]

Answer:

acute angle measure less than 90 degrees, right angle measure 90 degrees, Obtuse angle measure more than 90 degrees, straight angle equal to 180 degrees, reflex angle is an angle greater than 180° and less than 360°, complementary angle either of two angles whose sum is 90°, supplementary angle either of two angles whose sum is 180°

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2 years ago