True
Carbon monoxide is a primary pollutant which no odor results from incomplete combustion of fuel. The man sources are gasoline and burning of biomass.
Depending on the source of emission, pollutants can be classified into two groups that is primary and secondary pollutants.
A primary pollutant is emitted in the atmosphere directly from a source. It can be either natural sch as volcanic eruptions, sandstorms or man-made that is due to industrial and vehicle emissions. Examples of primary pollutants are nitrogen oxides, carbon monoxide and particulate matter.
Secondary pollutant is due to interactions between primary and secondary pollutants. These can be chemical or physical interactions. Examples are photo-chemical oxidants and secondary particulate matter.
Therefore, carbon monoxide CO is a primary pollutant.
Answer:
It is not a gas because its particles do not have large spaces between them.
Explanation:
Answer:
The volume of hydrogen gas generated by given reaction is 9.48 L
Explanation:
Firstly, we calculate the mole of Zinc added, n = 25.5 / 65 = 0.392 mol
With the same equivalent, the mole of generated hydrogen gas will be the same, at 0.392 mol.
Secondly, we get the equation
<em>P . V = n . R . T</em>
with P (pressure, atm), V (volume, litre), n (mole, mol), R (ideal gas constant, 0.082), T (temperature, Kelvin)
So we have to convert the given information to correct unit
P = 742 mmHg = 0.976 atm
T = 15 °C = 288 K
Hence we can calculate the generated volume by
V = n . R . T / P = 0.392 x 0.082 x 288 / 0.976 = 9.48 L
Answer:
1. 67.2 kJ/mol
Explanation:
Using the derived expression from Arrhenius Equation
Given that:
time 
= 8.3 days = (8.3 × 24 ) hours = 199.2 hours
time 
= 10.6 hours
Temperature 
= 0° C = (0+273 )K = 273 K
Temperature 
= 30° C = (30+ 273) = 303 K
Rate = 8.314 J / mol
Since 
Then we can rewrite the above expression as:
