A 10 gram sample of H20 is sealed in a 1350 ml flask at 27°C. Given the fact that water has a vapor pressure of 26.7 mmHg at thi
1 answer:
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Explanation:
Let the volume of the solution be 100 ml.
As the volume of glycol = 50 = volume of water
Hence, the number of moles of glycol =
=
=
= 0.894 mol
Hence, number of moles of water =
= 2.77
As glycol is dissolved in water.
So, the molality =
= 17.9
Therefore, the expected freezing point =
=
Thus, we can conclude that the expected freezing point is .
Answer:
<h3>The answer is 0.075 moles</h3>Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
We have the final answer as
<h3>0.075 moles</h3>Hope this helps you