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erik [133]
3 years ago
6

If a turtle can move 2 1/2 miles every hour, then how many hours would it take for a turtle to go 5 miles

Mathematics
1 answer:
posledela3 years ago
3 0

Answer:

12.5 hours to go 5 miles

Step-by-step explanation:

2 1/2 x 5 = 12.5

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Each edge of a cube measures 8.9 cm.<br><br> What is the surface area of the cube?
Alina [70]
S.A=(s×s)×6
As a result, the surface area of the cube is 475.26 square cm. Hope it help!
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2 years ago
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What percentage of 100 is 35
nika2105 [10]

Answer:

35%

You divide 35 to 100

35÷100=0.35

and its equal to

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Marvin has a standard deck of cards, what is the probability of 5?
Nonamiya [84]

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Step-by-step explanation:

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23j-21g+20e-13+52e-37j+45-49e<br> (Like terms)
eduard

The solution to the algebraic expression is: 23e - 21g - 14j + 32

What are algebraic expressions?

Algebraic expressions are mathematical expressions that contain variables, coefficients, and arithmetic operations such as addition, subtraction, division, and multiplication.

Solving algebraic expressions are an important part of mathematics as it helps to improve the aptitude and solving skills of the students.

From the given information, we have;

23j - 21g + 20e - 13 + 52e - 37j + 45 - 49e

let's rearrange by taking the like terms to the same sides;

= 23j -37j - 21g + 20e + 52e - 49e - 13 + 45

= -14j - 21g + 23e + 32

= 23e - 21g - 14j + 32

Therefore, we can conclude that the solution to the algebraic expression is: 23e - 21g - 14j + 32

Learn more about solving algebraic expressions here:

brainly.com/question/4344214

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3 0
1 year ago
Verify sine law by taking triangle in 4 quadrant<br>Explain with figure.<br>​
Ksivusya [100]

Proof of the Law of Sines

The Law of Sines states that for any triangle ABC, with sides a,b,c (see below)

a

 sin  A

=

b

 sin  B

=

c

 sin  C

For more see Law of Sines.

Acute triangles

Draw the altitude h from the vertex A of the triangle

From the definition of the sine function

 sin  B =

h

c

    a n d        sin  C =

h

b

or

h = c  sin  B     a n d       h = b  sin  C

Since they are both equal to h

c  sin  B = b  sin  C

Dividing through by sinB and then sinC

c

 sin  C

=

b

 sin  B

Repeat the above, this time with the altitude drawn from point B

Using a similar method it can be shown that in this case

c

 sin  C

=

a

 sin  A

Combining (4) and (5) :

a

 sin  A

=

b

 sin  B

=

c

 sin  C

- Q.E.D

Obtuse Triangles

The proof above requires that we draw two altitudes of the triangle. In the case of obtuse triangles, two of the altitudes are outside the triangle, so we need a slightly different proof. It uses one interior altitude as above, but also one exterior altitude.

First the interior altitude. This is the same as the proof for acute triangles above.

Draw the altitude h from the vertex A of the triangle

 sin  B =

h

c

      a n d          sin  C =

h

b

or

h = c  sin  B       a n d         h = b  sin  C

Since they are both equal to h

c  sin  B = b  sin  C

Dividing through by sinB and then sinC

c

 sin  C

=

b

 sin  B

Draw the second altitude h from B. This requires extending the side b:

The angles BAC and BAK are supplementary, so the sine of both are the same.

(see Supplementary angles trig identities)

Angle A is BAC, so

 sin  A =

h

c

or

h = c  sin  A

In the larger triangle CBK

 sin  C =

h

a

or

h = a  sin  C

From (6) and (7) since they are both equal to h

c  sin  A = a  sin  C

Dividing through by sinA then sinC:

a

 sin  A

=

c

 sin  C

Combining (4) and (9):

a

 sin  A

=

b

 sin  B

=

c

 sin  C

7 0
2 years ago
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