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3 years ago

Please help :) .....................

Mathematics

1 answer:

Kay [80]3 years ago

8 0

There are web sites and videos that stand ready to show you how to bisect an angle.

The basic idea is that you draw an arc through both rays so that the points of intersection are the same distance from the vertex. Then, you construct a perpendicular bisector of the segment between those intersection points. That will bisect the angle.

For (3), you bisect each of the angles made by the original bisector. (1/2 of 1/2 = 1/4)

You might be interested in

If anyone knows about definite integrals for calculus then please I request help! I

kicyunya [14]

Answer:

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

U-Substitution

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution.

Set u: $\displaystyle u = 4x^{-2}$
[u] Differentiate [Basic Power Rule, Derivative Properties]: $\displaystyle du = \frac{-8}{x^3} \ dx$
[Bounds] Switch: $\displaystyle \left \{ {{x = 9 ,\ u = 4(9)^{-2} = \frac{4}{81}} \atop {x = 5 ,\ u = 4(5)^{-2} = \frac{4}{25}}} \right.$

Step 3: Integrate Pt. 2

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^9_5 {\frac{-8}{x^3}e^\big{4x^{-2}}} \, dx$
[Integral] U-Substitution: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^{\frac{4}{81}}_{\frac{4}{25}} {e^\big{u}} \, du$
[Integral] Exponential Integration: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}(e^\big{u}) \bigg| \limits^{\frac{4}{81}}_{\frac{4}{25}}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8} \bigg( e^\Big{\frac{4}{81}} - e^\Big{\frac{4}{25}} \bigg)$
Simplify: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

4 0

3 years ago

A car and a bus set out at 2 p.M. From the same point, headed in the same direction. The speed of the car is 30mph slower than t

Blizzard [7]

Answer:

Car = 10 miles/hour

Bus = 20 miles/hour

Step-by-step explanation:

Here,

Let, the value of the speed of the bus = X

the value of the speed of the car = 2X - 30 (As the speed of the car is 30mph slower than twice)

According to the question,

2X - 20 = 2*(2x-30)

or, 2X - 20 = 4X-60

or, 2X = 40

x = 20

Therefore, the speed of the bus, x = 20 miles/hour

So, the speed of the car is (2*20-30) mph = (40 - 30) mph = 10 miles/hour.

6 0

4 years ago

Fifteen minutes past eight in the evening on a 24 hour clock

anastassius [24]

Answer: The time is 20:15 on a military time clock.

Step-by-step explanation:

4 0

3 years ago

The temperature in minneapolis changed from -7 degrees at 6 am to 7 degrees Fahrenheit at noon. How much did the temperature inc

kotegsom [21]

It increased 14 degrees Fahrenheit

5 0

3 years ago

Paulo can run a marathon in four hours and 20 minutes. If he's able to cut of 18% of his time, how long will it take him to run

Inga [223]

Cut out 18%
100=all,
all-cut out=remaining
100-18=82

4hrs 20mins=240+20mins=260mins
82% of 260 is 0.82*20=213.2=3 hours and 33.2 minutes

he can runi s 3 hours and 33.2 minutes

7 0

3 years ago