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Irina18 [472]
3 years ago
10

Will give brainliest!!!!!!!!!!!!!!!

Mathematics
1 answer:
Sati [7]3 years ago
3 0
Perpendicular: slope is -3/2

Based on this I would already know the answer is A.
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at which values of x does the graph of f(x)=x^2-x-2/(x^2-1)(x^2-16) have a vertical asymptope? check all that apply
katen-ka-za [31]

Answer:

x = -4, 1, 4

Step-by-step explanation:

The function is given as:

f(x) = (x² - x -2)/[(x² - 1)(x² -16)]

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3 0
3 years ago
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