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AfilCa [17]
4 years ago
6

Prime factorization of 39

Mathematics
1 answer:
Black_prince [1.1K]4 years ago
4 0
Lets quickly run through the prime numbers and see what it is not divisible by

39 is not divisible by 2
39 IS divisible by 3

So lets stop right here.

What is 39 divided by 3? 13 !

And 13 is a prime number too!

So that is all we can do.

So prime factorization of 39 is <u>3 x 13</u><u><em /></u>
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3(x-4)+2(×+1) I need help
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Answer:

Simplify:

5x - 10

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You have in the class 11 boys and 8 girls. You also have 3 seniors, 4 juniors, and 12 sophomores. If you select a student at ran
Daniel [21]

Answer:

38

Step-by-step explanation:

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3 years ago
What is the radical form of the expression 432 ? PLEASE HELP!!!!!
oksano4ka [1.4K]

Answer:

12√3

Step-by-step explanation:

well first divide 432 by 3

that gives you 144

so you have 144×3

you then but them both in radicals

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therefore the answer is 12√3

4 0
3 years ago
What is 5,267 rounded to the nearest ten?
Soloha48 [4]

Answer:

2,270

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
En la división sintética sólo son tomados en cuenta los coeficientes del divisor?
Airida [17]

La división sintetica sirve para el cociente entre polinomios, la cual es particularmente util para cuando tenemos un numerador de grado alto y un denominador de grado 1.

Veremos que si, en la división sintética solo son tomados en cuenta los coeficientes del divisor.

Para explicarla, usaremos un ejemplo.

x^3 - 2x^2 + 5x + 3  será el <u>numerador</u>

x - 2 será el <u>denominador.</u>

Para poder aplicar la división sintetica, el maximo exponente en el <u>denominador </u>debe ser uno.

Así, nuestro cociente es:

\frac{x^3 - 2x^2 + 5x + 3}{x-2}

Procedemos a igualar el <u>denominador</u> a cero:

x - 2 = 0

x = 2

Ahora veremos los coeficientes del <u>numerador</u> (el <u>numerador </u>es el <u>divisor</u>).

Lo que debemos hacer es tomar cada coeficiente (comenzando por los que multiplican a los terminos con mayor exponente) y multiplicarlos por este número.

En este caso, el primer coeficiente es 1.

2*1 = 2

Ahora le sumamos esto al proximo coeficiente, que es -2:

-2 + 2 = 0

Multiplicamos esto por el valor de x, que es 2.

2*0 = 0

Ahora sumamos esto al proximo coeficiente, que es 5

5 + 0  = 5

Multiplicamos esto por el valor de x, que es 2:

5*2 = 10

Sumamos esto al ultimo coeficiente, que es 3.

10 + 3 = 13

Este ultimo valor es el residuo, y los primeros 3 números que obtuvimos son los coeficientes del cociente, entonces el cociente será:

1*x^2 + 0*x + 10 = x^2 + 10

Como vimos, solo usamos los coeficientes del numerador/divisor para realizar esta operación, por lo que si, solo los coeficientes del divisor son tomados en cuenta.

Si quieres aprender más, puedes leer:

brainly.com/question/10466403

3 0
3 years ago
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