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Yanka [14]
3 years ago
9

In the diagram below, MNPQ is a parallelogram whose diagonals are perpendicular. Prove: MNPQ is a rhombus.

Mathematics
1 answer:
katen-ka-za [31]3 years ago
4 0

Answer:

Given : MNPQ is a parallelogram whose diagonals are perpendicular.

To prove :  MNPQ is a rhombus.

Proof:

In parallelogram MNPQ,

R is the intersection point of the diagonals MP and NQ( shown in below diagram)

\implies MR\cong RP (Because, the diagonals of parallelogram bisects each other)

\angle MRQ\cong \angle QRP (Right angles )

QR\cong QR  (Reflexive)

Thus, By SAS postulate of congruence,

\triangle MRQ\cong \triangle PRQ

By CPCTC,

MQ\cong QP

Similarly,

We can prove, \triangle MRN\cong \triangle PRN

By CPCTC,

MN\cong NP

But, By the definition of parallelogram,

MN\cong QP and MQ\cong NP

⇒ MN\cong NP\cong PQ\cong MQ

All four side of parallelogram MNQP are congruent.

⇒ Parallelogram MNPQ is a rhombus.

Hence, proved.

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