if you have a rectangle with a length of 0.5 x + 10 feet and a width of 6 feet how could you find the area written in its simple
1 answer:
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<h2>Hope this helps!</h2>
Answer:
x + 20 = area
Step-by-step explanation:
You need to recall the equation for a rectangle:
Width x Length = Area
So simply plug the values into this:
(0.5x+10) * 6
(0.5x * 6) + (10 * 6)
= 3x + 60
Simplified down by dividing by three:
= area
<h2>Hope this helps!</h2>
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Answer:
2.794
Step-by-step explanation:
Recall that if G(x,y) is a parametrization of the surface S and F and G are smooth enough then
F can be written as
F(x,y,z) = (xy, yz, zx)
and S has a straightforward parametrization as
with 0≤ x≤1 and 0≤ y≤1
So
we also have
and so
we just have then to compute a double integral of a polynomial on the unit square 0≤ x≤1 and 0≤ y≤1
=1/3+2-2/9-2/5+3/2-1/4-1/6 = 2.794
Answer:
Option (B)
Step-by-step explanation:
Length of PR = 4
RS = 4
QS = 4
For the length of PT,
PT² = RT² + PR² [Since, PT is the diagonal of rectangle PRT]
PT² = QS² + PR² [Since, RT ≅ QS]
PT² = 4² + 7²
PT² = 16 + 49
PT² = 65
Now for the length of PQ,
PQ² = QT² + PT²
PQ² = RS² + PT² [Since, QT ≅ RS]
PQ² = 4² + 65
PQ² = 16 + 65
PQ = √81
PQ = 9
Therefore, length of diagonal PQ is 9 units.
Option (B) will be the answer.
