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likoan [24]
2 years ago
14

if you have a rectangle with a length of 0.5 x + 10 feet and a width of 6 feet how could you find the area written in its simple

st form
Mathematics
1 answer:
Greeley [361]2 years ago
3 0
<h2>Greetings!</h2>

Answer:

x + 20 = area

Step-by-step explanation:

You need to recall the equation for a rectangle:

Width x Length = Area

So simply plug the values into this:

(0.5x+10) * 6

(0.5x * 6) + (10 * 6)

= 3x + 60

Simplified down by dividing by three:

\frac{3x}{3} + \frac{60}{3} = area

<h3>x + 20 = area</h3>
<h2>Hope this helps!</h2>
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Vika [28.1K]

Answer:

The answer is 856.17.

Step-by-step explanation:

If you made the fraction into a decimal, you would get 856.166666666. If you round it to the nearest hundredth, you would get 856.17.

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valentinak56 [21]

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In a certain region of space, the potential is given by v=2x−5x2y 3yz2. How much is the magnitude of the electric field at point
Masja [62]

The magnitude of the electric field at the point (-2, 2, 0) is 46.52 V/m

<h3>How to calculate the electric field?</h3>

Since in a certain region of space, the potential is given by v = 2x − 5x²y 3yz²,

The electric field, E = -grad(V) where grad(V) = (dV/dx)i + (dV/dy)j + (dV/dz)k

Since V = 2x − 5x²y + 3yz²

dV/dx = d(2x − 5x²y + 3yz²)/dx

= d2x/dx - d5x²y/dx + d3yz²/dx

= 2 - 10xy + 0

= 2 - 10xy

dV/dy = d(2x − 5x²y + 3yz²)/dy

= d2x/dy - d5x²y/dy + d3yz²/dy

= 0 - 5x² + 3z²

=  - 5x² + 3z²

dV/dz = d(2x − 5x²y + 3yz²)/dz

= d2x/dz - d5x²y/dz + d3yz²/dz

= 0 - 0 + 6z

=  6z

<h3>The electric field</h3>

So, E = -grad(V)

= -[(dV/dx)i + (dV/dy)j + (dV/dz)k]

= -[(2 - 10xy)i + (- 5x² + 3z²)j + (6z)k]

So, the electric field at (-2, 2, 0) is

E = -[(2 - 10xy)i + (- 5x² + 3z²)j + (6z)k]

E = -[(2 - 10(-2)(2))i + (- 5(2)² + 3(0)²)j + (6(0))k]

E = -[(2 + 40)i + (- 5(4) + 0)j + (0)k]

E = -[42i + (-20 + 0)j + (0)k]

E = -[42i - 20j + 0k]

E = -42i + 20j - 0k

<h3>The magnitude of the electric field</h3>

So, the magnitude of E at (-2, 2, 0) is

|E| = √[(-42)² + 20² + 0²]

=  √[1764 + 400 + 0]

= √2164

= 46.52 V/m

So, the magnitude of the electric field at the point (-2, 2, 0) is 46.52 V/m

Learn more about electric field here:

brainly.com/question/25751825

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3 0
1 year ago
If coal is mined at $35.99 per short ton, how much is the price per kg? Use dimensional analysis to solve. 1 short ton = 907 kg.
cricket20 [7]

The cost of 1kg of coal mined from the ore is $0.0397

Data;

  • 1 ton = $35.99
  • 1kg = ?

<h3>The Cost of 1kg of Coal</h3>

To find the cost of 1kg of coal, we can simply and equate 1 ton to its equivalent in ton and the solve.

1ton = 907kg\\

let's write this and equate it

1 ton = $35.99

907kg = $35.99

1kg = x

Let's cross multiply both sides and solve for x

907kg = \$35.99\\1kg = x\\x = \frac{1 * 35.99}{907} \\x = \$0.0397

The cost of 1kg of coal is $0.0397

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2 years ago
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