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olga55 [171]
3 years ago
15

(THIS IS A TEST I NEED HELP)

Mathematics
1 answer:
Leya [2.2K]3 years ago
4 0

Answer:

Option (B)

Step-by-step explanation:

Length of PR = 4

RS = 4

QS = 4

For the length of PT,

PT² = RT² + PR² [Since, PT is the diagonal of rectangle PRT]

PT² = QS² + PR² [Since, RT ≅ QS]

PT² = 4² + 7²

PT² = 16 + 49

PT² = 65

Now for the length of PQ,

PQ² = QT² + PT²

PQ² = RS² + PT² [Since, QT ≅ RS]

PQ² = 4² + 65

PQ² = 16 + 65

PQ = √81

PQ = 9

Therefore, length of diagonal PQ is 9 units.

Option (B) will be the answer.

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Answer:

With all the lines, I may be wrong. But I'm confident that line B has a slope of 2.

This is because it rises up 2 up the y axis for every one unit on the x axis.

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Please help with algebra problem
kumpel [21]
Number of weekend minutes used: x
Number of weekday minutes used: y

This month Nick was billed for 643 minutes:
(1) x+y=643

The charge for these minutes was $35.44
Telephone company charges $0.04 per minute for weekend calls (x)
and $0.08 per minute for calls made on weekdays (y)
(2) 0.04x+0.08y=35.44

We have a system of 2 equations and 2 unkowns:
(1) x+y=643
(2) 0.04x+0.08y=35.44

Using the method of substitution
Isolating x from the first equation:
(1) x+y-y=643-y
(3) x=643-y

Replacing x by 643-y in the second equation
(2) 0.04x+0.08y=35.44
0.04(643-y)+0.08y=35.44
25.72-0.04y+0.08y=35.44
0.04y+25.72=35.44

Solving for y:
0.04y+25.72-25.72=35.44-25.72
0.04y=9.72

Dividing both sides of the equation by 0.04:
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y=243

Replacing y by 243 in the equation (3)
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Answers:
The number of weekends minutes used was 400
The number of weekdays minutes used was 243
6 0
3 years ago
I need help. Someone please help. The second and third picture are to the same problem. Just please help me I'm dumb.
kirill115 [55]

By listing the samples in descending order we have - Sample B, Sample E, Sample A, Sample C, and Sample D.

Step-by-step explanation:

Step 1; First, we must convert all the temperatures into a common scale. The given temperatures are in three different units i.e. °C, K, and °F. Here we convert all the units into K.

To convert °C to K, we add 273.15 with the °C , 44 °C= 44 + 273.15 =     317.15 K.

To convert °F, we have the formula (112°F − 32) × (\frac{5}{9}) + 273.15, so

110 °F = (110 - 32) × (\frac{5}{9}) + 273.15 = 316.483 K,

112 °F = (112 - 32) × (\frac{5}{9}) + 273.15 = 317.594 K.

Step 2; By rewriting all the values on the same unit, we get;

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Sample C = 316.483 K,

Sample D = 310 K,

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The descending order is as follows 320 K, 317.594K, 317.15 K, 316.483 K and 310 K which is Sample B, Sample E, Sample A, Sample C, and Sample D.

5 0
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Montano1993 [528]

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5 0
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