(THIS IS A TEST I NEED HELP)
1 answer:
Answer:
Option (B)
Step-by-step explanation:
Length of PR = 4
RS = 4
QS = 4
For the length of PT,
PT² = RT² + PR² [Since, PT is the diagonal of rectangle PRT]
PT² = QS² + PR² [Since, RT ≅ QS]
PT² = 4² + 7²
PT² = 16 + 49
PT² = 65
Now for the length of PQ,
PQ² = QT² + PT²
PQ² = RS² + PT² [Since, QT ≅ RS]
PQ² = 4² + 65
PQ² = 16 + 65
PQ = √81
PQ = 9
Therefore, length of diagonal PQ is 9 units.
Option (B) will be the answer.
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Answer:
3, 5, 7, 9, 11, .........
Step-by-step explanation:
Given
= n(n + 2) , then
S₁ = 1(1 + 2) = 1(3) = 3 ⇒ a₁ = 3
S₂ = 2(2 + 2) = 2(4) = 8
S₃ = 3(3 + 2) = 3(5) = 15
Thus
a₂ = S₂ - S₁ = 8 - 3 = 5
a₃ = S₃ - S₂ = 15 - 8 = 7
The first 3 terms are 3, 5, 7
This is an AP with common difference d = 2, then
a₄ = a₃ + 2 = 7 + 2 = 9
a₅ = a₄ + 2 = 9 + 2 = 11
and so on