3 years ago

Question 1 (1 point)

Mathematics

1 answer:

Vladimir [108]3 years ago

4 0

The ordered pair (1,5) would be the correct answer.

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Jadyn prepares a bag of candy before a road trip. The bag contains individual pieces of Skittles, M&Ms, Life Savers and Sour

kipiarov [429]

Given condition is- The bag contains individual pieces of Skittles, M&Ms, Life Savers and Sour Patch Kids.

Let the total number of candies in the bag be = x

Then, Skittles are $\frac{1x}{2}$

Candies left = $x-\frac{x}{2}$ = $\frac{x}{2}$

M&Ms are = $\frac{1x}{8}$

Now remaining candies are= $\frac{3x}{8}$

Now Life savers are = $\frac{9x}{32}$

Now adding all these 3 candies

$\frac{x}{2}+ \frac{x}{8}+\frac{9x}{32}$

= $\frac{29x}{32}$

Now the remaining candies sour patch will be =

$x-\frac{29x}{32} =\frac{3x}{32}$

Hence, sour patch kids are $\frac{3}{32}$

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3 years ago

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ANEK [815]

Answer:

-26.71579

Step-by-step explanation:

Any scientific or graphing calculator can evaluate this expression for you.

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3 years ago

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S_A_V [24]

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Anton [14]

F(2)=42(2)-100
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AURORKA [14]

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When you simply the fraction you get 6^15 or 470184984576.

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