Answer
a) y | p(y)
25 | 0.8
100 | 0.15
300 | 0.05
E(y) = ∑ y . p(y)
E(y) = 25 × 0.8 + 100 × 0.15 + 300 × 0.05
E(y) = 50
average class size equal to E(y) = 50
b) y | p(y)
25 | 
100 | 
300 | 
E(y) = ∑ y . p(y)
E(y) = 25 × 0.4 + 100 × 0.3 + 300 × 0.3
E(y) = 130
average class size equal to E(y) = 130
c) Average Student in the class in a school = 50
Average student at the school has student = 130
Answer:
6(2x-3)= -9 given
12x-18= -9 distribute
12x-18+18= -9+18 addition
12x= 9 division
x= 3/4 solution
Step-by-step explanation:
Answer:
Step-by-step explanation:
Surface area is pretty synonymous with area.
How much paint is needed to paint the outside of a birdhouse?
Paint is measured in volume, so not surface area
How much wallpaper is needed to cover the walls of your room?
Since its just the walls its not total surface area, but surface area of the walls.
How much water will it take to fill a rectangular container?
water is measured in volume, especially when wanting to fill something.
How much topsoil can a gardener place in his wheelbarrow?
Wants to know how much topsoil is needed to FILL the wheelbarrow, filling is volume. So not surface area.
How much fabric is needed to make a pillowcase for a pillow?
Not asking to fill the pillowcase, just how much is needed for the thin, one layer thick case. So this is surface area.
A(n) = a₁.(r)ⁿ⁻¹, where a₁ = 1st term, r= common ratio and n, the rank
In the formula given a₁ = 5, r = 3/2 and n = 6 (we have to find the 6th term value).
a₆ = 5.(3/2)⁶⁻¹ = 5.(3/2)⁵ = 1215/32 (answer C)
Answer:
3
Step-by-step explanation:
= 3
