For this case we have the following function:

By definition, we have that the domain of a function is given by all the values for which the function is defined. The given function is not defined when the denominator is zero.
So:

Thus, the function is not defined at 
The domain is given by all real numbers except 2.
Answer:
The domain is given by all real numbers except 2.
<span>−y−3(−3y+5)
= </span><span>−y + 9y - 15
= 8y - 15
answer
</span><span>d.8y-15</span>
Divide both sides by -6 and don't forget to flip the inequality symbol
-7>d
d<-7
Answer:
The fourth term of the sequence B(4) =-8
The sequence is 1,-2,4,-8...
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given that the sequence
B(n) = 1(-2)ⁿ⁻¹
Put n=1
B(1) = 1(-2)¹⁻¹ = 2⁰ =1
Put n=2
B(2) = 1(-2)²⁻¹ = (-2)¹ =-2
Put n=3
B(3) =1(-2)³⁻¹ = (-2)² =4
Put n=4
B(4) = 1(-2)⁴⁻¹ =(-2)³ =-8
The sequence
1,-2,4,-8...
Answer:
B) -2
Step-by-step explanation:
m=(y2-y1)/(x2-x1)=(2-(-10))/(-4-2)=(2+10)/-6=12/-6=-2