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Softa [21]
3 years ago
12

Kelly has 7 1/4 yards of rope. She cuts 3 inches off each end of the rope. Kelly will divide the remaining rope into 5 equal pie

ces for a craft project. What will be the length of each piece of rope?
Mathematics
1 answer:
lana [24]3 years ago
3 0
If you take 3 inches off each end, that means you will be taking 6 inches off. If you take 6 inches away from 7 1/4 yards ,(7 yards, 9 inches,) you get 7 1/12 yards (7 yards, 3 inches).

(7 1/12) / 5 = 1.426repeating

So each piece of rope will be (Approximately) 1.4 or 1 2/5 yards.


(I think.)

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A quadratic graph will surely help you find the solutions

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The item costs $900 after the 90% off.

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kamal has 2 liters of soup. he pours it into 4 bowls each bowl gets an equal amount how many milliliters of soup are in each bow
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At 2 PM, a thermometer reading 80°F is taken outside where the air temperature is 20°F. At 2:03 PM, the temperature reading yiel
Alexeev081 [22]
Use Law of Cooling:
T(t) = (T_0 - T_A)e^{-kt} +T_A
T0 = initial temperature, TA = ambient or final temperature

First solve for k using given info, T(3) = 42
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Substituting k back into cooling equation gives:
T(t) = 60(\frac{11}{30})^{t/3} + 20

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
T(t) = (x-80)(\frac{11}{30})^{t/3} + 80 \\  \\ 71 = (x-80)(\frac{11}{30})^{\frac{10-t}{3}} + 80
Solve for x:
x = -9(\frac{11}{30})^{\frac{t-10}{3}} + 80
Sub back into original cooling equation, x = T(t)
-9(\frac{11}{30})^{\frac{t-10}{3}} + 80 = 60 (\frac{11}{30})^{t/3} +20
Solve for t:
60 (\frac{11}{30})^{t/3} +9(\frac{11}{30})^{\frac{-10}{3}}(\frac{11}{30})^{t/3}  = 60 \\  \\  (\frac{11}{30})^{t/3} = \frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}} \\  \\  \\ t = 3(\frac{ln(\frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}})}{ln (\frac{11}{30})}) \\  \\ \\  t = 4.959

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM
8 0
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