The vertical asymptotes for a rational expression, occur at the values of "x" that make the denominator 0, and therefore the expression undefined.
what are those anyway? simple, just set the denominator to 0, solve for "x", and that will spit them out.
x + 4 = 0
x = -4
there, if "x" ever becomes -4, then the fraction turns to

thus, that's where the vertical asymptote is at, x = -4.
Answer:
n - 4
Step-by-step explanation:
6 - x = 2
8 - x = 4
9 - x = 5
n - x = ?
->
x = 4
n - 4
Hi there! :)

Solve for j(h(x)):
h(x) = x² + 4
j(x) = 4x - 1
Substitute in h(x) into "x":
j(h(x)) = 4(x² + 4) - 1
j(h(x)) = 4x² + 16 - 1
j(h(x)) = 4x² + 15
Solve at x = 2:
4(2)² + 15 = 4(4) + 15 = 31.
Answer:
600
Step-by-step explanation:
set x as the number
x0.10 = 60
x = 60/0.10
x = 600
Answer:
Hello!
An irrational number is all the real numbers which are not rational numbers.
M =
is a irrational number.
N =
is a irrational number.
S = 2 is not irrational, and is actually a whole number.
T = 5 is not irrational, and is actually a whole number.
Have a great day!
I hope this helps! <33