Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
X/8 - 10 = x/3
bring the values with the variable on one side
x/3 - x/8 = 10
find a common denominator and subtract these fractions
8x/24 - 3x/24 = -10
now subtract fractions
8x - 3x = 5x
5x/24 = -10
multiply both sides by 24
5x = -240
divide both sides by 5
x = -48
the number is -48
Answer:
5,376in^3
Step-by-step explanation:
find the volume of the smaller box first
10×4×12 = 480in^3
find volume of bigger box
17×12×24 = 4,896in^3
add both volumes 4,896 +480 = 5,376in^3
<u>Answer:</u>
The line equation that passes through the given points is 7x – y = 13
<u>Explanation:</u>
Given:
Two points are A(2, 1) and B(3, 8).
To find:
The line equation that passes through the given two points.
Solution:
We know that, general equation of a line passing through two points (x1, y1), (x2, y2) in point slope form is given by
..........(1)
here, in our problem x1 = 3, y1 = 8, x2 = 2 and y2 = 1.
Now substitute the values in (1)
y – 8 = 7(x – 3)
y – 8 = 7x – 21
7x – y = 21 – 8
7x – y = 13
Hence, the line equation that passes through the given points is 7x – y = 13
Answer:
A, B and C
Step-by-step explanation:
A) 3 and 18 = has 3 as factor
B) 8 and 24 = has 3 as factor
C) 12 and 18 = has 3 as factor
D) 1 and 3 = has as factor of 1 and 3
so the answer is A, B and C
