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2 years ago

Please help me plssssssssssssssssssssss

Mathematics

2 answers:

oksian1 [2.3K]2 years ago

7 0

Problem 7

(45 pages)/(90 min) = 1/2 page per min, i.e. 1 page per 2 minutes

(60 pages)(120 min) = 1/2 page per min

Both lead to the same result, so yes they are proportional.

Their reading speed is identical.

<h3>Answer: True</h3>

andreev551 [17]2 years ago

7 0

$\huge{\textbf{\textsf{{\color{navy}{An}}{\red{sw}}{\orange{er}} {\color{yellow}{:}}}}}$

Thanks
Hope it helps

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The scale on a map is 1: 75 000. (a) Calculate the ACTUAL distance, in km, between two places which are 16 cm apart on the map.

finlep [7]

Answer:

a. 1 200 000 km

b. 0.000 773 cm

c. 67 500 000 000 km²

d. 0.000 000 016 cm²

Step-by-step explanation:

a. Calculate the ACTUAL distance, in km, between two places which are 16 cm apart on the map.

Since the scale is 1 : 75000 that is 1 cm : 75000 km, we want to find the actual distance of 16 cm on the map. Let x be the actual distance in km.

So, 1 cm : 75000 km = 16 cm : x km

So, 1 cm/75000 km = 16 cm/x km

Thus x km = 16 cm × 75000 km/1 cm = 1 200 000 km

(b) Calculate length of a road on the map which is 0.58 km.

Let y be the length of road on the map. So, using our scale

1 cm : 75000 km = y cm : 0.58 km

So, 1 cm/75000 km = y cm/0.58 km

Thus y cm = 0.58 km × 1 cm/75000 km = 0.000 773 cm

(c) Calculate, in km², the ACTUAL area of a lake which is 12 cm2 on the map.

Since the scale is 1 : 75000 , the scale for the area would be the square of this. So, 1² : 75000² = 1 : 5 625 000 000 which is 1 cm² : 5 625 000 000 km²

Let z be the actual area of the lake.

So, 1 cm² : 5 625 000 000 km² = 12 cm² : z km²

So, 1 cm²/5 625 000 000 km² = 12 cm²/z km²

Thus z km² = 12 cm² × 5 625 000 000 km²/1 cm² = 67 500 000 000 km²

(d) Calculate the area of a play field on the map which has has an actual area of 90 km².

Let a represent the area of the play field on the map. Using our scale for the area,

1 cm² : 5 625 000 000 km² = a cm² : 90 km²

So, a cm² = 90 km² × 1/5 625 000 000 km² = 0.000 000 016 cm²

4 0

3 years ago

(a) Find a 90% confidence interval for the population mean price (per 100 pounds) that farmers in this region get for their wate

Anon25 [30]

Answer:

The margin of error (E) $=0.49$

Step-by-step explanation:

Given,

mean $\bar{x}=6.88$

standard deviation $\sigma=1.90$

sample size $n=41$

$90\% \quad \text{confidence interval}$

Critical value $=\frac{z_\alpha}{2}\quad \quad\quad[\because\;\alpha=1-\text{confidence interval}]$

$=1-0.90$

$\Rightarrow \alpha=0.1$

Critical value $=\frac{z_{0.1}}{2}$

$=z_{0.05}$

$=1.645$

The margin of error (E) $=\frac{z_\alpha}{2} \times\frac{\sigma}{\sqrt{n} }$

$=1.645\times\frac{1.90}{\sqrt{41} }$

$=0.49$

Hence, The margin of error (E) $=0.49$

Complete question is attached in below.

7 0

3 years ago

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

Orlov [11]

$ax+bx-c=0 \\
x(a+b)-c=0 \\
x(a+b)=c \\
x= \frac{c}{a+b}$

7 0

3 years ago

Answers for both boxes please

Dafna11 [192]

Answer y=25/3 or 8.33333 and x=0.4444443

Step-by-step explanation:

y=4(y-7/3)+3 y=4y-28+3 y=4y-25

7 0

3 years ago

Question 2 of 10

mylen [45]

Answer:

Y=(x+4)*2-3

=x*2+8x+16-3

=x*2+8x+13

So the standard form is B

4 0

3 years ago