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2 years ago

Please help me plssssssssssssssssssssss

Mathematics

2 answers:

oksian1 [2.3K]2 years ago

7 0

Problem 7

(45 pages)/(90 min) = 1/2 page per min, i.e. 1 page per 2 minutes

(60 pages)(120 min) = 1/2 page per min

Both lead to the same result, so yes they are proportional.

Their reading speed is identical.

<h3>Answer: True</h3>

andreev551 [17]2 years ago

7 0

$\huge{\textbf{\textsf{{\color{navy}{An}}{\red{sw}}{\orange{er}} {\color{yellow}{:}}}}}$

Thanks
Hope it helps

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Help!! Question on probability. Wi give brainliest!!

Aleks [24]

Answer:

$P = \frac{5}{282} = 0.0177$

Step-by-step explanation:

First we need to find the total amount of apples in the crate:

Total = 10 + 14 + 4 + 18 = 46 apples

The probability of the first apple being a golden delicious apple is the number of those apples over the total number of apples:

$P(golden) = \frac{N(golden)}{N(total)}$

$P(golden) = \frac{4}{48} = \frac{1}{12}$

Then, the probability of the second apple being a granny Smith apple is the number of those apples over the total number of apples, but now the total number of apples is one less, because one apple was removed from the crate:

$P(granny) = \frac{N(granny)}{N(total)-1}$

$P(granny) = \frac{10}{47}$

The final probability we want is the product of those two probabilities:

$P = P(golden) * P(granny) = \frac{1}{12} \frac{10}{47} = \frac{10}{564} = \frac{5}{282}= 0.0177$

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3 years ago

A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals

andrew11 [14]

Answer:

A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals in his cattle? Here the number of animals and the number of days are in inverse proportion. Hence the food will last 4 days.

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3 years ago

Maya's history test had 40 questions. She answered 95% of the items correctly. How many questions did Maya answer correctly?

ankoles [38]

Maya got 38 of them right

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2 years ago

Read 2 more answers

the train travels 16 miles in 20 minutes, at this rate how, many muients will it take to travel12 miles

lana66690 [7]

Answer:

sorry if this is confusing

Step-by-step explanation:

16 miles = 12 miles

------------ ----------------

20 mins. how many mins?

16 = 12 cross multiply 16? = 240 divide by 16 240 divided by 16 = 15 miles

20 ? because 15 x 16 = 240

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3 years ago

Help this is the last question to a test

goblinko [34]

You’re a Horrible Person
Solutions are given in alphabetical order (k, x, y, z)

[(1, 0, 0, 1), (1, 0, 1, 0), (1, 1, 0, 0), (2, 0, 1, 1), (2, 1, 0, 1), (2, 1, 1, 0), (3, 1, 1, 1), (8, 0, 0, 2), (8, 0, 2, 0), (8, 2, 0, 0), (9, 0, 1, 2), (9, 0, 2, 1), (9, 1, 0, 2), (9, 1, 2, 0), (9, 2, 0, 1), (9, 2, 1, 0), (10, 1, 1, 2), (10, 1, 2, 1), (10, 2, 1, 1), (16, 0, 2, 2), (16, 2, 0, 2), (16, 2, 2, 0), (17, 1, 2, 2), (17, 2, 1, 2), (17, 2, 2, 1), (24, 2, 2, 2), (27, 0, 0, 3), (27, 0, 3, 0), (27, 3, 0, 0), (28, 0, 1, 3), (28, 0, 3, 1), (28, 1, 0, 3), (28, 1, 3, 0), (28, 3, 0, 1), (28, 3, 1, 0), (29, 1, 1, 3), (29, 1, 3, 1), (29, 3, 1, 1), (35, 0, 2, 3), (35, 0, 3, 2), (35, 2, 0, 3), (35, 2, 3, 0), (35, 3, 0, 2), (35, 3, 2, 0), (36, 1, 2, 3), (36, 1, 3, 2), (36, 2, 1, 3), (36, 2, 3, 1), (36, 3, 1, 2), (36, 3, 2, 1), (43, 2, 2, 3), (43, 2, 3, 2), (43, 3, 2, 2), (54, 0, 3, 3), (54, 3, 0, 3), (54, 3, 3, 0), (55, 1, 3, 3), (55, 3, 1, 3), (55, 3, 3, 1), (62, 2, 3, 3), (62, 3, 2, 3), (62, 3, 3, 2), (64, 0, 0, 4), (64, 0, 4, 0), (64, 4, 0, 0), (65, 0, 1, 4), (65, 0, 4, 1), (65, 1, 0, 4), (65, 1, 4, 0), (65, 4, 0, 1), (65, 4, 1, 0), (66, 1, 1, 4), (66, 1, 4, 1), (66, 4, 1, 1), (72, 0, 2, 4), (72, 0, 4, 2), (72, 2, 0, 4), (72, 2, 4, 0), (72, 4, 0, 2), (72, 4, 2, 0), (73, 1, 2, 4), (73, 1, 4, 2), (73, 2, 1, 4), (73, 2, 4, 1), (73, 4, 1, 2), (73, 4, 2, 1), (80, 2, 2, 4), (80, 2, 4, 2), (80, 4, 2, 2), (81, 3, 3, 3), (91, 0, 3, 4), (91, 0, 4, 3), (91, 3, 0, 4), (91, 3, 4, 0), (91, 4, 0, 3), (91, 4, 3, 0), (92, 1, 3, 4), (92, 1, 4, 3), (92, 3, 1, 4), (92, 3, 4, 1), (92, 4, 1, 3), (92, 4, 3, 1), (99, 2, 3, 4), (99, 2, 4, 3), (99, 3, 2, 4), (99, 3, 4, 2), (99, 4, 2, 3), (99, 4, 3, 2)]

3 0

3 years ago