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guapka [62]
3 years ago
12

According to Newton’s Second Law of Motion, an object will accelerate if which kind of force is applied?

Physics
2 answers:
Kobotan [32]3 years ago
7 0

Answer:

unbalanced force

Explanation:

this is a guess so just look it up

Darina [25.2K]3 years ago
5 0
Answer is A unbalanced force

Explanation: I just looked it up
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A 1.3-kg model airplane flies in a circular path on the end of a 23-m line. The plane makes
storchak [24]

(a) The plane makes 4.3 revolutions per minute, so it makes a single revolution in

(1 min) / (4.3 rev) ≈ 0.2326 min ≈ 13.95 s ≈ 14 s

(b) The plane completes 1 revolution in about 14 s, so that in this time it travels a distance equal to the circumference of the path:

(2<em>π</em> (23 m)) / (14 s) ≈ 10.3568 m/s ≈ 10 m/s

(c) The plane accelerates toward the center of the path with magnitude

<em>a</em> = (10 m/s)² / (23 m) ≈ 4.6636 m/s² ≈ 4.7 m/s²

(d) By Newton's second law, the tension in the line is

<em>F</em> = (1.3 kg) (4.7 m/s²) ≈ 6.0627 N ≈ 6.1 N

4 0
3 years ago
Faraday's Law states that the negative of the time rate of change of the flux of the magnetic field through a surface is equal t
MrRa [10]

Answer:

(C). The line integral of the magnetic field around a closed loop

Explanation:

Faraday's law states that induced emf is directly proportional to the time rate of change of magnetic flux.

This can be written mathematically as;

EMF = -\frac{\delta \phi _B}{\delta t}

(\frac{\delta \phi _B}{\delta t} ) is the rate of change of the magnetic flux through a surface bounded by the loop.

ΔФ = BA

where;

ΔФ is change in flux

B is the magnetic field

A is the area of the loop

Thus, according to Faraday's law of electric generators

∫BdL = \frac{\delta \phi _B}{\delta t} = EMF

Therefore, the line integral of the magnetic field around a closed loop is equal to the negative of the rate of change of the magnetic flux through the area enclosed by the loop.

The correct option is "C"

(C). The line integral of the magnetic field around a closed loop

8 0
4 years ago
One kind of slingshot consists of a pocket that holds a pebble and is whirled on a circle of radius r. The pebble is released fr
Debora [2.8K]

Answer:

θ=142.9°

Explanation:

d=1 *r

angle ϕ= 37.1°

the line connecting pebble and target should be tangent to a circle so

cos(180-ϕ-θ)=\frac{r}{d}=\frac{1}{1}

∴ θ=180-ϕ-cos^{-1} (\frac{1}{1} )

  θ= 180-37.1-0

  θ=142.9°

 

5 0
3 years ago
A 500 kg car traveling at 20 m/s rear ends another car of 600 kg at rest. The collision is great enough that the two cars stick
aksik [14]

Answer: its 50

Explanation:

im waffling does anybody have syrup

4 0
3 years ago
A 13-N east horizontal force acts in the same direction as a 6.4kg block as it slides 2.5m/s on a frictionless, horizontal surfa
MaRussiya [10]

Answer:

6.77 m/s

Explanation:

Acceleration = Force/mass;

The block is accelerated by 13/6.4 m/s^2 for 2.1s from an initial velocity of 2.5m/s.

Applying the equation of motion:

Vf=Vi + at

Where Vf is the final velocity, Vi is the initial velocity, a is the acceleration and t is the time for which the object accelerates.

<h3>Vf= 2.5 + ((13/6.4)*2.1);</h3>
8 0
3 years ago
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