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prisoha [69]
3 years ago
7

You arrive at an intersection with traffic lights that are not working because of a power outage. What do you do?

Physics
2 answers:
d1i1m1o1n [39]3 years ago
8 0
You act as it is a four way stop
solmaris [256]3 years ago
5 0
I'm not sure if this is a school question or a question that you asked because you want to know (Quora is better for this), but I would:

Look around and see what everyone else is doing. Are any of them on phones? How many? If a lot of them are, they're probably calling police and I'd wait for police to arrive. If there was a lot if distress I'd get out of my car and call in my loudest voice to wait for police to come regulate traffic.

If no one else is calling police, I'd call. Tell them to send someone over as fast as they can to regulate traffic, and tell them what I think the importance level is, based on how many cars are backed up.

If people are still trying to drive, I'd try to get everyone to stop and wait for police to come regulate traffic. Stand on my car, call out, use a sign, make a sign, whatever I could think of. Use a whistle if I had one.

When the police came, I'd do what they told me to.

If I was on my way to work, I'd call my boss and say, "you probably know by now, but the traffic lights aren't working. I don't think I can be there in time."
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Is everyone in your class able to hear a quiet sound equally well?
Sergio039 [100]

Answer:

No

Explanation:

Loudness describes how people perceive sound (see loudness). ... If people could hear equally well at all frequencies, the contour lines would be flat because the same measured sound intensity would be perceived to be equally loud regardless of the sound frequency. In fact, people do not hear as well at low frequencies.

8 0
3 years ago
If a current­-carrying wire has a cross­-sectional area that gradually becomes smaller along the length of the wire, the drift v
jarptica [38.1K]

Answer:d

Explanation:

Drift velocity is given by

v_d=\frac{I}{n\times Q\times A}

where v_d=drift velocity

I=Current

n=no of electron

Q=charge of Electron

A=cross-section

If area of cross-section decreases gradually then drift velocity will increase because drift velocity is inversely proportional to Area of cross-section

       

6 0
3 years ago
to what height will a 250g soccer ball rise to if it is kicked directly upwards at 8 meters per second​
Nonamiya [84]

Answer:

3.2 m

Explanation:

we know

Hmax = V²/2g

= 8² / 2*10 = 3.2

6 0
3 years ago
Read 2 more answers
A screen is placed 1.20m behind a single slit. The central maximum in the resulting diffraction pattern on the screen is 1.40cm
andrew11 [14]

Answer:

2.8 cm

Explanation:

y_1 = Separation between two first order diffraction minima = 1.4 cm

D = Distance of screen = 1.2 m

m = Order

Fringe width is given by

\beta_1=\dfrac{y_1}{2}\\\Rightarrow \beta_1=\dfrac{1.4}{2}\\\Rightarrow \beta_1=0.7\ cm

Fringe width is also given by

\beta_1=\dfrac{m_1\lambda D}{d}\\\Rightarrow d=\dfrac{m_1\lambda D}{\beta_1}

For second order

\beta_2=\dfrac{m_2\lambda D}{d}\\\Rightarrow \beta_2=\dfrac{m_2\lambda D}{\dfrac{m_1\lambda D}{\beta_1}}\\\Rightarrow \beta_2=\dfrac{m_2}{m_1}\beta_1

Distance between two second order minima is given by

y_2=2\beta_2

\\\Rightarrow y_2=2\dfrac{m_2}{m_1}\beta_1\\\Rightarrow y_2=2\dfrac{2}{1}\times 0.7\\\Rightarrow y_2=2.8\ cm

The distance between the two second order minima is 2.8 cm

8 0
3 years ago
A flat uniform circular disk (r= 2.00m,
dusya [7]

Incomplete question.The Complete question is here

A flat uniform circular disk (radius = 2.00 m, mass = 1.00 ✕ 102 kg) is initially stationary. The disk is free to rotate in the horizontal plane about a friction less axis perpendicular to the center of the disk. A 40.0-kg person, standing 1.25 m from the axis, begins to run on the disk in a circular path and has a tangential speed of 2.00 m/s relative to the ground.

a.) Find the resulting angular speed of the disk (in rad/s) and describe the direction of the rotation.

b.) Determine the time it takes for a spot marking the starting point to pass again beneath the runner's feet.

Answer:

(a)ω = 1 rad/s

(b)t = 2.41 s

Explanation:

(a) initial angular momentum = final angular momentum  

0 = L for disk + L............... for runner

0 = Iω² - mv²r ...................they're opposite in direction

0 = (MR²/2)(ω²) - mv²r ................where is ω is angular speed which is required in part (a) of question

0 = [(1.00×10²kg)(2.00 m)² / 2](ω²) - (40.0 kg)(2.00 m/s)²(1.25 m)

0=200ω²-200

200=200ω²

ω = 1 rad/s

b.)

lets assume the "starting point" is a point marked on the disk.

The person's angular speed is  

v/r = (2.00 m/s) / (1.25 m) = 1.6 rad/s

As the person and the disk are moving in opposite directions, the person will run part of a revolution and the turning disk would complete the whole revolution.

(angle) + (angle disk turns) = 2π

(1.6 rad/s)(t) + ωt = 2π

t[1.6 rad/s + 1 rad/s] = 2π

t = 2.41 s

6 0
3 years ago
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