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prisoha [69]
3 years ago
7

You arrive at an intersection with traffic lights that are not working because of a power outage. What do you do?

Physics
2 answers:
d1i1m1o1n [39]3 years ago
8 0
You act as it is a four way stop
solmaris [256]3 years ago
5 0
I'm not sure if this is a school question or a question that you asked because you want to know (Quora is better for this), but I would:

Look around and see what everyone else is doing. Are any of them on phones? How many? If a lot of them are, they're probably calling police and I'd wait for police to arrive. If there was a lot if distress I'd get out of my car and call in my loudest voice to wait for police to come regulate traffic.

If no one else is calling police, I'd call. Tell them to send someone over as fast as they can to regulate traffic, and tell them what I think the importance level is, based on how many cars are backed up.

If people are still trying to drive, I'd try to get everyone to stop and wait for police to come regulate traffic. Stand on my car, call out, use a sign, make a sign, whatever I could think of. Use a whistle if I had one.

When the police came, I'd do what they told me to.

If I was on my way to work, I'd call my boss and say, "you probably know by now, but the traffic lights aren't working. I don't think I can be there in time."
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Explanation:

Velocity = displacement / time

v = √((58 m)² + (135 m)²) / (12 min × 60 s/min)

v = 0.20 m/s

7 0
3 years ago
A wave can be described as?
aleksley [76]

Answer:

<em>B) The disturbance of particles in an area.</em>

Explanation:

<em>A wave involves transmission of  energy from one place to another by the actual disturbance of the particles of the medium.</em>

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6 0
3 years ago
The rocket's acceleration has components \(a_{x}(t)= \alpha t^{2}\) and \(a_{y}(t)= \beta - \gamma t\), where \(\alpha = 2.50 {\
lbvjy [14]
 it is just a matter of integration and using initial conditions since in general dv/dt = a it implies v = integral a dt 
v(t)_x = integral a_{x}(t) dt = alpha t^3/3 + c the integration constant c can be found out since we know v(t)_x at t =0 is v_{0x} so substitute this in the equation to get v(t)_x = alpha t^3 / 3 + v_{0x} 
similarly v(t)_y = integral a_{y}(t) dt = integral beta - gamma t dt = beta t - gamma t^2 / 2 + c this constant c use at t = 0 v(t)_y = v_{0y} v(t)_y = beta t - gamma t^2 / 2 + v_{0y} 
so the velocity vector as a function of time vec{v}(t) in terms of components as[ alpha t^3 / 3 + v_{0x} , beta t - gamma t^2 / 2 + v_{0y} ] 
similarly you should integrate to find position vector since dr/dt = v r = integral of v dt 
r(t)_x = alpha t^4 / 12 + + v_{0x}t + c let us assume the initial position vector is at origin so x and y initial position vector is zero and hence c = 0 in both cases 
r(t)_y = beta t^2/2 - gamma t^3/6 + v_{0y} t + c here c = 0 since it is at 0 when t = 0 we assume 
r(t)_vec = [ r(t)_x , r(t)_y ] = [ alpha t^4 / 12 + + v_{0x}t , beta t^2/2 - gamma t^3/6 + v_{0y} t ] 
5 0
3 years ago
If an ideal gas does not exist then why laws were stated?
mihalych1998 [28]
That is because it is impossible to create a law for the behavior of every single different gas, so creating laws for an ideal gas helps us understand the basic nature of gasses which might or might not differ slightly or a lot. By understanding how an ideal gas works, we can understand how a normal gas works.
5 0
3 years ago
An elastic conducting material is stretched into a circular loop of 9.65 cm radius. It is placed with its plane perpendicular to
Nadya [2.5K]

Answer:

The induced emf in the coil is 0.522 volts.                        

Explanation:

Given that,

Radius of the circular loop, r = 9.65 cm

It is placed with its plane perpendicular to a uniform 1.14 T magnetic field.

The radius of the loop starts to shrink at an instantaneous rate of 75.6 cm/s , \dfrac{dr}{dt}=-0.756\ m/s

Due to the shrinking of radius of the loop, an emf induced in it. It is given by :

\epsilon=\dfrac{-d\phi}{dt}\\\\\epsilon=\dfrac{-d(BA)}{dt}\\\\\epsilon=B\dfrac{-d(\pi r^2)}{dt}\\\\\epsilon=2\pi rB\dfrac{dr}{dt}\\\\\epsilon=2\pi \times 9.65\times 10^{-2}\times 1.14\times 0.756\\\\\epsilon=0.522\ V

So, the induced emf in the coil is 0.522 volts.                                

8 0
3 years ago
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