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prisoha [69]
3 years ago
7

You arrive at an intersection with traffic lights that are not working because of a power outage. What do you do?

Physics
2 answers:
d1i1m1o1n [39]3 years ago
8 0
You act as it is a four way stop
solmaris [256]3 years ago
5 0
I'm not sure if this is a school question or a question that you asked because you want to know (Quora is better for this), but I would:

Look around and see what everyone else is doing. Are any of them on phones? How many? If a lot of them are, they're probably calling police and I'd wait for police to arrive. If there was a lot if distress I'd get out of my car and call in my loudest voice to wait for police to come regulate traffic.

If no one else is calling police, I'd call. Tell them to send someone over as fast as they can to regulate traffic, and tell them what I think the importance level is, based on how many cars are backed up.

If people are still trying to drive, I'd try to get everyone to stop and wait for police to come regulate traffic. Stand on my car, call out, use a sign, make a sign, whatever I could think of. Use a whistle if I had one.

When the police came, I'd do what they told me to.

If I was on my way to work, I'd call my boss and say, "you probably know by now, but the traffic lights aren't working. I don't think I can be there in time."
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Please answer this.
lilavasa [31]

Answer:

the answer is c

Explanation:

it's c because the moon has to be a full moon to be a solar eclipse when the sun moon and earth line up

6 0
3 years ago
Read 2 more answers
A 1.5 kg spherical ball is has a radius of 50 cm is rotating with angular velocity of 12 revolutions per minute. Determine the r
kykrilka [37]

Answer:

K.E = 0.0075 J

Explanation:

Given data:

Mass of the ball = 1.5 kg

radius, r = 50 cm = 0.5 m

Angular speed, ω = 12 rev/min = (12/60) rev/sec = 0.2 rev/sec

Now,

the kinetic energy is given as:

K.E = K.E=\frac{1}{2}I\omega^2

where,

I is the moment of inertia = mr²

on substituting the values, we get

K.E=\frac{1}{2}\times1.5\times0.5^2\times0.2^2

or

K.E = 0.0075 J

3 0
3 years ago
Lightwaves travel from the air into a lens made of glass. Their velocity decreases as they enter the glass. How does this affect
Papessa [141]
The waves become longer but slower
4 0
3 years ago
What have psychologists learned about perception from optical illusions ?
ruslelena [56]

Answer:

Explanation:

That an optical illusion somehow interferes with the way we see things. Even simple illusions can completely fool us. If you search out the term, you'll see all kinds of them.

Most critically we see one thing and know another to be true. But knowing the truth doesn't help us. We still see and believe the truth of the illusion.

5 0
3 years ago
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A brick and a feather fall to the earth at their respective terminal velocities. Which objectexperiences the greater force of ai
Karo-lina-s [1.5K]

Answer:

Under the reasonable assumption that the brick has more mass than the feather, the brick experiences a greater force of air friction.

Explanation:

<u>Objects at terminal velocity</u>, only under the influence of gravity, have maximized their speed and <u>have an acceleration of zero</u>.  Thus, neither object is accelerating.

Recall Newton's second law: \sum {\vec {F}}=m \vec {a}

Since acceleration for each object is zero, the sum of the force acting on each of those objects must also be zero.

Since the only forces acting on the objects are gravity and the force of air friction, in order to zero out, <u>the force of air friction must be equal in magnitude and opposite in direction to the force of gravity</u>.

Recall that near the surface of the earth, F_{gravity}=mg, so <u>the Force of Gravity acting on an object is directly proportional to the object's mass</u>.  <em>(A similar argument could be made even if this were not taking place on the surface of the earth, so long as the objects were the same distance from the object providing gravitational influence).</em>

If the masses of the objects are different, <u>the object with the greater mass will experience</u> a larger force of gravity, and hence <u>a larger force of air friction</u> at terminal velocity.  

Under the reasonable assumption that the brick has more mass than the feather, the brick experiences a greater force of air friction.

4 0
2 years ago
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