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Black_prince [1.1K]
3 years ago
7

It takes a 7N force to cause a 0.028 kg object to begin moving. What is the acceleration of the object as it begins to move?

Physics
2 answers:
galben [10]3 years ago
6 0

Answer:

250 m/s2

Hope u find this helpful

Explanation:

Force = mass x acceleration

7N = (0.028kg) (a)

7N/0.028kg = a

a = 250m/s2

lbvjy [14]3 years ago
3 0
A is the answer to the question of what jersey is the name of the the team that is he still playing with the soccer team game today and he has a soccer ball with the wwwwwwww
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Explanation:

Given that,

Diameter = 10 cm

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Av_{1}=Av_{2}

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(II). We need to calculate the pressure the gauge pressure

Using Bernoulli equation

P_{1}+\dfrac{1}{2}\rho v_{1}^2+\rho gh_{1}=P_{2}+\dfrac{1}{2}\rho v_{2}^2+\rho g h_{2}

P_{2}=P_{1}+\dfrac{1}{2}\rho(v_{1}^2-v_{2}^2)-\rho g(h_{1}-h_{2})

P_{2}=2\times10^{5}+\dfrac{1}{2}\times1000(4-49)-1000\times 9.8\times(5)

P_{2}=1.28500\times10^{5}\ Pa

(III).  If it is possible to carry water to a faucet 17 m above ground,

Using Bernoulli equation

P_{1}+\dfrac{1}{2}\rho v_{1}^2+\rho gh=P_{3}+\dfrac{1}{2}\rho v_{3}^2+\rho g h_{3}

P_{3}=P_{1}+\dfrac{1}{2}\rho v_{1}^2-\rho g(h_{1}-h_{3})

Here, h_{3}=0

Put the value in the equation

P_{3}=2\times10^{5}+\dfrac{1}{2}\times1000\times4-1000\times 9.8\times17

P_{3}=3.5400\times10^{5}\ Pa

Hence, This is required solution.

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