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3 years ago

The radius of a circle is 5 inches. What is the circle's diameter?

Mathematics

2 answers:

Sedaia [141]3 years ago

7 0

Answer:

Step-by-step explanation:

Radius is half of diameter so if radius is 5 then the diamiter is 10

Hope this helps!!

Anastasy [175]3 years ago

6 0

Answer:

10 inches

Step-by-step explanation:

Simply,multiply radius by 2...

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1. The hypotenuse of a right triangle has a length of 10.0 and one of its

Mamont248 [21]

Answer:

I wont tell you the answer but I can tell you how to solve this one.

Step-by-step explanation:

If they are both squared then square them. Once you have the hypotenuse and the leg squared subtract the leg from the hypotenuse. That's your answer. Then you un- square it by finding the square root of the new number. That square root is your answer

7 0

3 years ago

How do I solve this equation: -5/6b + 3/4 = 1/2b - 2/3 ?

Gre4nikov [31]

First get like things on the same side:
-5/6b - 1/2b= -2/3 - 3/4

Then find equivalent fractions to make the equation easier to solve.
-5/6b - 3/6b= -8/12 - 9/12

Then just add things together and solve.
-8/6b= -17/12
-8b= 6(-17/12)
-8b= -17/2
b= (-17/2)/-8
b= 17/16

You can then plug the answer back into the original question to make sure it is the correct answer.

3 0

3 years ago

Evaluate the surface integral. s x2 + y2 + z2 ds s is the part of the cylinder x2 + y2 = 4 that lies between the planes z = 0 an

Leya [2.2K]

Parameterize the lateral face $T_1$ of the cylinder by

$\mathbf r_1(u,v)=(x(u,v),y(u,v),z(u,v))=(2\cos u,2\sin u,v$

where $0\le u\le2\pi$ and $0\le v\le3$ , and parameterize the disks $T_2,T_3$ as

$\mathbf r_2(r,\theta)=(x(r,\theta),y(r,\theta),z(r,\theta))=(r\cos\theta,r\sin\theta,0)$
$\mathbf r_3(r,\theta)=(r\cos\theta,r\sin\theta,3)$

where $0\le r\le2$ and $0\le\theta\le2\pi$ .

The integral along the surface of the cylinder (with outward/positive orientation) is then

$\displaystyle\iint_S(x^2+y^2+z^2)\,\mathrm dS=\left\{\iint_{T_1}+\iint_{T_2}+\iint_{T_3}\right\}(x^2+y^2+z^2)\,\mathrm dS$
$=\displaystyle\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}((2\cos u)^2+(2\sin u)^2+v^2)\left\|{{\mathbf r}_1}_u\times{{\mathbf r}_2}_v\right\|\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+0^2)\left\|{{\mathbf r}_2}_r\times{{\mathbf r}_2}_\theta\right\|\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+3^2)\left\|{{\mathbf r}_3}_r\times{{\mathbf r}_3}_\theta\right\|\,\mathrm d\theta\,\mathrm dr$
$=\displaystyle2\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r^3\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r(r^2+9)\,\mathrm d\theta\,\mathrm dr$
$=\displaystyle4\pi\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv+2\pi\int_{r=0}^{r=2}r^3\,\mathrm dr+2\pi\int_{r=0}^{r=2}r(r^2+9)\,\mathrm dr$
$=136\pi$

7 0

3 years ago

A recipe for a loaf of bread calls for of a cup of flour. If Milo used 12 cups of flour, how many loaves of bread did he prepare

Free_Kalibri [48]

Answer:

D) 12 loaves

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

11w+5w-1=65w-36<br> Ayuden poniendo tambien el procedimiento plis

nevsk [136]

Answer:

w=1.4

Step-by-step explanation:

11w+5w-1=65w-36

16w-1=65w-36

16w-65w= -36+1

-49w= -35

w= -35/-49

w= 1.4

4 0

3 years ago