Solve each using mental math.
1 answer:
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The equation of tangent to the circle at the point (-6,8) is -6x+8y=100.
Given the equation of circle
and point at which the tangent meets the circle is (-6,8).
A tangent to a circle is basically a line at point P with coordinates is a straight line that touches the circle at P. The tangent is perpendicular to the radius which joins the centre of circle to the point P.
Linear equation looks like y=mx+c.
Tangent to a circle of equation at (z,t) is:
xz+ty=.
We have to just put the values in the formula above to get the equation of tangent to the circle at (-6,8).
It will be as under:
x(-6)+y(8)=100
-6x+8y=100
Hence the equation of tangent to the circle at the point (-6,8) is -6x+8y=100.
Learn more about tangent of circle at brainly.com/question/17040970
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Answer:
A. 320
Step-by-step explanation:
See attachment for the figure
in order to determine Area of quadrilateral ABDF, we'll use the formula i.e
Area of quadrilateral ABDF = Area of AECD - Area of ΔBCD - Area of ΔDEF ->eq(1)
whereas, area of AECD = (AC × AE)
Area of ΔBCD = 1/2 (BC x CD)
Area of ΔDEF =1/2 ( EF x ED)
Substituting in eq(1)
eq(1)=>
Area of quadrilateral ABDF = (AC × AE) - 1/2 (BC x CD)- 1/2 ( EF x ED)
=(32 x 20) - 1/2(16 x 20) - 1/2(10 x 32)
= 640 - 160 - 160
= 640 - 320
= 320 square unit
Therefore, the area of quadrilateral ABDF is 320 square unit
