Answer:
(a) 2800 J
(b) 31.28 %
Explanation:
Heat intake, Q1 = 8950 J
Heat discard, Q2 = 6150 J
(a) Work = intake heat energy - discarded heat energy
W = Q1 - Q2 = 8950 - 6150 = 2800 J
(b) Efficiency = 1 - Q2 / Q1
Efficiency = 1 - (6150 / 8950) = 0.3128 = 31.28%
Answer: Fusion, vaporization, and sublimation are endothermic processes, whereas freezing ... Changes of state are examples of phase changes, or phase … ... liquid to gas, or solid to gas) requires an input of energy; it is endothermic. ... rate: A–B: heating solid ice; B–C: melting ice; C–D: heating liquid water; D–E: ...
Explanation:
Answer:
U1 = U2 since the temperature inside the balloon does not change
Q1 - W1 = Q2 - W2
Work done by the balloon = W2 - W1 (on the environment)
W2 - W1 = Q2 - Q1 = 75 J heat put into balloon
So the balloon does 75 J on the environment
Since direction is part of velocity, and the object is moving in a circle, its velocity is constantly changing.
Answer:
The sound intensity of source #2 is 38.3 W/m²
Explanation:
Given;
sound intensity of source #1, I₁ = 38.3 W/m²
sound intensity of source #2, I₂ = 2.6 dB greater than 38.3 W/m²
To determine he sound intensity of source #2 in W/m², we must convert 2.6 dB to sound intensity in W/m².
Thus, sound intensity of source #2 = 38.3 W/m² + 1.8197 x 10⁻¹² W/m² = 38.3 W/m²
Therefore, the sound intensity of source #2 is 38.3 W/m²